CODEWITHSUNDEEP
javaregexscala
Sayim Khan
Sayim Khan

Reputation: 82

regex to replace characters in a string

I have a string like this val str = "luckycore.util.BigNum("0")", the first five character of the string e.g lucky are dynamic and can change while rest of the string is fixed, what I was trying was to get output as luckyInt(0) i.e replace all charaters except dynamic one with Int and also remove quotes around 0, I tried using replace and substring methods and its working fine for me, but I want to get this output using regex, I tried but nothing is working, someone please help.

one more case is:

 input string = richardcore.util.BigNum("0")

 output string = richardInt(0)

Upvotes: 1

Views: 112

Answers (3)

Aamir
Aamir

Reputation: 2424

There is no need for Regex, you can simply do it:

val str = """luckycore.util.BigNum("0")"""
val l = str.replace(str.substring(str.indexOf("core"),str.indexOf("(")).trim,"Int").replace("\"","")

Upvotes: 1

Leo C
Leo C

Reputation: 22439

If I understand your requirement correctly, there is no need for Regex. You can define a simple function (in Scala) as follows:

// Replace substring trailing after the first n characters 
def replaceTail(s: String, n: Int, tail: String) = {
  s.substring(0, n) + tail
}

val str1 = """luckycore.util.BigNum("0")"""
replaceTail(str1, 5, "Int(0)")
res1: String = luckyInt(0)

val str2 = """richardcore.util.BigNum("0")"""
replaceTail(str2, 7, "Int(0)")
res2: String = richardInt(0)

Upvotes: 0

Abhinav Galodha
Abhinav Galodha

Reputation: 9878

You can try using the Regex ([a-z]{5})(core\.util\.BigNum\(\"0\"\)) and then replace the String with the first captured Group.

You can play with this regex at https://regex101.com/r/1DhgLo/1

I am not familiar with Scala or Java. But the Regex should be pretty much remain the same.

Upvotes: 1

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