Reputation: 4796
Transferred from Code Review. If this question is not suitable for SO either, please let me know. I will remove it.
I am working on an algorithm puzzle here at: https://www.hackerrank.com/challenges/hackerland-radio-transmitters/forum
It cannot pass all of the test cases. Some test cases have such large arrays that it gets so hard to debug. Simple cases from my end seem all work fine. Can anyone look into this and share what is wrong with this algorithm? Basically it just loops through the array and find every furthest covered station (as origin
). A counter-like variable result
record the origins (radio stations).
def solution(k, arr, origin=0):
arr = sorted(list(set(arr)))
result = 1
cur = 0
origin = 0
for i in range(1, len(arr)):
if arr[i] - arr[origin] <= k:
pass
else:
origin = i - 1
j = 1
while origin + j < len(arr):
if arr[origin + j] - arr[origin] <= k:
pass
else:
origin = origin + j
i = origin + j + 1
result += 1
continue
j += 1
return result
Upvotes: 2
Views: 106
Reputation: 2416
Most of your code is correct. Only problem is with the usage of For range outer loop and continue in the inner loop.
The following code passed all the test cases
def solution(k, arr, origin=0):
arr = sorted(list(set(arr)))
print arr
result = 1
cur = 0
origin = 0
i = 0
while (i < len(arr)):
if arr[i] - arr[origin] <= k:
i = i + 1
pass
else:
origin = i - 1
j = 1
while origin + j < len(arr):
if arr[origin + j] - arr[origin] <= k:
pass
else:
# Start for next station position from this point
i = origin + j
origin = i
# need another radio station
result += 1
break
j += 1
return result
hope it helps!
Upvotes: 2
Reputation: 503
You're placing the first object on the first index. The first object in the optimal solution can be placed later too.
solution(1,[1,2,3,4,5,6])
prints 3, when it should be 2 (by placing the two objects on 2 and 5). You place your first object on 1, then 3 and then 5. It should ideally be placed on 2, then 5.
Upvotes: 1