CODEWITHSUNDEEP
bashfile
Adarsh
Adarsh

Reputation: 1

Bash: read a file contents till some pattern match and Store in another file

I have got a text file containing some data which is separated by a dashed line. I need to store each days data in a separate file with <filename>_yyyymmdd.

Input_file:

01-01-2017
Some text data
--------------------------
10-10-2017
Some text data
--------------------------

So far I have tried is: Have some errors in the code.

while read line; do
    if [[ $line =~ ^[0-9]{2}-[0-9]{2}-[0-9]{4}$ ]] ; then; fi
done > Input_file

I am trying to read the date format from the file and creating a new file and appending data format to it.

Upvotes: 0

Views: 831

Answers (1)

anubhava
anubhava

Reputation: 785128

If you are looking for a bash solution then use:

#!/bin/bash

f="${1?needs a filename}"
while IFS= read -r line; do
   [[ $line =~ ^([0-9]{2})-([0-9]{2})-([0-9]{4})$ ]] &&
   fn="${f}_${BASH_REMATCH[3]}${BASH_REMATCH[2]}${BASH_REMATCH[1]}"
   [[ $line =~ ^-+$ ]] || echo "$line" >> "$fn"
done < "$f"

Otherwise this slightly verbose awk will also work:

awk '/^([0-9]{2})-([0-9]{2})-([0-9]{4})$/{
   split($0, a, "-"); if (fn) close(fn); fn = FILENAME "_" a[3] a[2] a[1]} 
   !/^-+$/{print $0 > fn}' filename

Upvotes: 1

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