Reputation: 389
I have to extract a specific part of an URL.
Example
original URLs
http://www.example.com/PARTiNEED/some/other/stuff
http://www.example.com/PARTiNEED
in case 1 I need to extract
/PARTiNEED/
and in case 2 I need to extract the same part but add an additional "/" at the end
/PARTiNEED/
What I've got right now is this
$tempURL = 'http://'. $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];
$tempURL = explode('/', $tempURL);
$tempURL = "/" . $tempURL[3] . "/";
is there a more convenient way to do this or is this solution fine?
Upvotes: 0
Views: 104
Reputation: 17433
It's normally a good idea to use PHP's built in functions for things like this where possible. In this case, the parse_url
method is designed for parsing URLs.
In your case:
// Extract the path from the URL
$path = parse_url($url, PHP_URL_PATH);
// Separate by forward slashes
$parts = explode('/', $path);
// The part you want is index 1 - the first is an empty string
$result = "/{$parts[1]}/";
Upvotes: 3
Reputation: 9703
This will give you proper idea about your requirment.
<?php
$url_array = parse_url("http://www.example.com/PARTiNEED/some/other/stuff");
$path = $url_array['path'];
var_dump($path);
?>
now you can use string explode function to get your job done.
Upvotes: 1
Reputation: 123
Here this should solve your problem
// check if the var $_SERVER['REQUEST_URI'] is set
if(isset($_SERVER['REQUEST_URI'])) {
// explode by /
$tempURL = explode('/', $_SERVER['REQUEST_URI']);
// what you need in in the array $tempURL;
$WhatUNeed = $tempURL[1];
} else {
$WhatUNeed = '/';
}
Dont worry about the trailing slash, that can be added anytime in your code.
$WhatUNeed = $tempURL[1].'/';
Upvotes: 1
Reputation: 433
You don't need this part:
'http://'. $_SERVER['SERVER_NAME']
you can just do:
$tempURL = explode('/', $_SERVER['REQUEST_URI']);
$tempURL = "/" . $tempURL[1] . "/";
Edited index from 0 to 1 as commented.
Upvotes: 1
Reputation: 747
Maybe regex suits your needs better?
$tempURL = "http://www.example.com/PARTiNEED/some/other/stuff"; // or $tempURL = "http://www.example.com/PARTiNEED
$pattern = '#(?<=\.com)(.+?)(?=/|$)#';
preg_match($pattern, $tempURL, $match);
$result = $match[0] . "/";
Upvotes: 1