Reputation: 6123
In the html I have 2 images within the .fig-8
anchor.
.img-active
= display: block
.img-inactive
= display: none
HTML:
<div class="tabs1">
<a class="fig-8" data-tab="tab1">
<img src="/path.png" class="img-active">
<img src="/selected.png" class="img-inactive">
</a>
<a class="fig-8" data-tab="tab2">
<img src="/path1.png" class="img-active">
<img src="/selected.png" class="img-inactive">
</a>
<a class="fig-8" data-tab="tab3">
<img src="/path2.png" class="img-active">
<img src="/selected.png" class="img-inactive">
</a>
</div>
All I need is that when you click on the anchor, .img-active
should be display: none
and .img-inactive
= display: block
As I am doing it in the js file:
$('.tabs1 a').on('click', function() {
$(this).find('.img-active').hide();
$(this).find('.img-inactive').show();
});
It is doing what I want but if you click on the second or third anchor, the images where I clicked are not getting to its original shape(the default image.).
Any suggestions?
Upvotes: 0
Views: 47
Reputation: 78520
Couldn't this be achieved using CSS? You can use the :focus
pseudo-class.
.img-inactive,.img-active {float:left;}
.img-inactive {display:none;}
.img-active {display:block;}
a:focus .img-inactive {display:block;}
a:focus .img-active {display:none;}
<div class="tabs1">
<a class="fig-8" data-tab="tab1" href="#">
<img src="//placehold.it/150/5C5/FFF?&text=active" class="img-active">
<img src="//placehold.it/150/C55/FFF?&text=inactive" class="img-inactive">
</a>
<a class="fig-8" data-tab="tab2" href="#">
<img src="//placehold.it/150/5C5/FFF?&text=active" class="img-active">
<img src="//placehold.it/150/C55/FFF?&text=inactive" class="img-inactive">
</a>
<a class="fig-8" data-tab="tab3" href="#">
<img src="//placehold.it/150/5C5/FFF?&text=active" class="img-active">
<img src="//placehold.it/150/C55/FFF?&text=inactive" class="img-inactive">
</a>
</div>
Otherwise, it's also pretty easy to do with jQuery
$('.tabs1 a').on('click', function() {
$('.tabs1 a .img-inactive').hide();
$('.tabs1 a .img-active').show();
$(this).find('.img-inactive').show();
$(this).find('.img-active').hide();
});
.img-inactive,.img-active {float:left;}
.img-inactive {display:none;}
.img-active {display:block;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="tabs1">
<a class="fig-8" data-tab="tab1" href="#">
<img src="//placehold.it/150/5C5/FFF?&text=active" class="img-active">
<img src="//placehold.it/150/C55/FFF?&text=inactive" class="img-inactive">
</a>
<a class="fig-8" data-tab="tab2" href="#">
<img src="//placehold.it/150/5C5/FFF?&text=active" class="img-active">
<img src="//placehold.it/150/C55/FFF?&text=inactive" class="img-inactive">
</a>
<a class="fig-8" data-tab="tab3" href="#">
<img src="//placehold.it/150/5C5/FFF?&text=active" class="img-active">
<img src="//placehold.it/150/C55/FFF?&text=inactive" class="img-inactive">
</a>
</div>
Upvotes: 2
Reputation: 1602
Can you try this:-
$('.tabs1 a').on('click', function() {
$('.img-active').not(this).show();
$('.img-inactive').not(this).hide();
$(this).find('.img-active').hide();
$(this).find('.img-inactive').show();
});
Upvotes: 1