CODEWITHSUNDEEP
vb.netftp
user7957951
user7957951

Reputation:

FtpWebRequest not recognizing the URI

My problem is I can’t seem to get the uri to work. The Error message says “Invalid URI: The format of the URI could not be determined”. Then I get this error message "The URI prefix is not recognized" when I try this line Dim ftpRequest As FtpWebRequest = CType(WebRequest.Create(ftpUri + ":" + port), FtpWebRequest)

Here’s what I have, and it works perfect when tested in filezilla:
Host: sftp.icecream.com
Username: softserve
Password: chocolate
Port: 22
destination folder: SoManyFlavors

here’s my code:

    Private Sub FtpUploadFile(ByVal fileToUpload As String, ByVal ftpUri As String, ByVal userName As String, ByVal password As String, ByVal port As String)

        Dim ftpRequest As FtpWebRequest = CType(WebRequest.Create(ftpUri), FtpWebRequest)

        Try
            ftpRequest.Method = WebRequestMethods.Ftp.UploadFile
            ftpRequest.Credentials = New NetworkCredential(userName, password)

            Dim bytes() As Byte = System.IO.File.ReadAllBytes(fileToUpload)

            ftpRequest.ContentLength = bytes.Length
            Using UploadStream As IO.Stream = ftpRequest.GetRequestStream()
                UploadStream.Write(bytes, 0, bytes.Length)
                UploadStream.Close()
            End Using
        Catch ex As Exception
            MessageBox.Show(ex.Message)
            Exit Sub
        End Try
    End Sub

my call:
FtpUploadFile("C:\Users\Desktop\icecream.txt", "sftp.icecream.com", "softserve", "chocolate", "22")
I also noticed there seem to be a few more options for ftp, but I’m not sure which one is best for my needs.

Upvotes: 0

Views: 1284

Answers (1)

Chris R. Timmons
Chris R. Timmons

Reputation: 2197

You need to specify the FTP protocol. Change your call to FtpUploadFile("C:\Users\Desktop\icecream.txt", "ftp://sftp.icecream.com", "softserve", "chocolate", "22").

You might get another error after fixing this error. The .Net FTP methods don't support SFTP, which is the kind of protocol it looks like you're code is trying to connect with.

Upvotes: 3

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