CODEWITHSUNDEEP
go
Chris G.
Chris G.

Reputation: 25954

http.Request: get file name from url

How do I get only the file name one.json from the following request: http://localhost/slow/one.json?

I just need to serve this file and others from the url? This is a test server that I need to respond very slow.

http.HandleFunc("/slow/", func(w http.ResponseWriter, r *http.Request) {
    log.Println("Slow...")
    log.Println(r.URL.Path[1:])
    time.Sleep(100 * time.Millisecond)
    http.ServeFile(w, r, r.URL.Path[1:])
})

Upvotes: 11

Views: 15734

Answers (2)

Adrian
Adrian

Reputation: 46413

I believe you are looking for path.Base: "Base returns the last element of path."

r,_ := http.NewRequest("GET", "http://localhost/slow/one.json", nil)
fmt.Println(path.Base(r.URL.Path))
// one.json

Playground link

Upvotes: 23

Chris G.
Chris G.

Reputation: 25954

Created two folders slow and fast and then I ended up using the following:

package main

import (
    "log"
    "net/http"
    "time"
    "fmt"
)

func main() {

    h := http.NewServeMux()

    h.HandleFunc("/fast/", func(w http.ResponseWriter, r *http.Request) {

        fmt.Println(r.URL.Path[1:])
        time.Sleep(100 * time.Millisecond)
        http.ServeFile(w, r, r.URL.Path[1:])

    })

    h.HandleFunc("/slow/", func(w http.ResponseWriter, r *http.Request) {

        fmt.Println(r.URL.Path[1:])
        time.Sleep(6000 * time.Millisecond)
        http.ServeFile(w, r, r.URL.Path[1:])

    })

    h.HandleFunc("/", func(w http.ResponseWriter, r *http.Request) {
        w.WriteHeader(404)
    })

    err := http.ListenAndServe(":8080", h)
    log.Fatal(err)
}

Upvotes: -2

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