Reputation: 727
I have a dropdown with a few disabled options. And I want make all options enabled.
This is html:
<select id="selectId">
<option value="JavaScript" disabled="">JavaScript</option>
<option value="Angular">Angular</option>
<option value="Backbone" disabled="">Backbone</option>
</select>
JavaScript:
var select = $("#selectId");
select.find("option").each(function(index, item) {
item.attr('disabled',false);
});
But I get an error: TypeError: item.attr is not a function. What's wrong here?
Upvotes: 2
Views: 5229
Reputation: 923
Using jQuery-3.5.1, this worked for me:
$("#selectId").find("option:disabled").removeAttr('disabled');
Upvotes: 1
Reputation: 29760
The correct way to alter properties (disabaled
is a property not an attribute) is to use prop
, see .prop() vs .attr():
$("#selectId option").prop('disabled', false);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<select id="selectId">
<option value="JavaScript" disabled="">JavaScript</option>
<option value="Angular">Angular</option>
<option value="Backbone" disabled="">Backbone</option>
</select>
You can set .attr('disabled',false);
but this doesn't work on every HTML element. The correct way to remove properties (disabled is a property and not an attribute) is prop
.
Your each
also doesn't return a jquery object, it returns a vanilla DOM element, hence the TypeError: item.attr is not a function.
. item
does not have a attr
function because it's not a jquery object.
Upvotes: 6
Reputation: 71
This one should work fine :)
$("#selectId option").each((i,items)=>{
$(items).attr('disabled',false)
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="selectId">
<option value="JavaScript" disabled="">JavaScript</option>
<option value="Angular">Angular</option>
<option value="Backbone" disabled="">Backbone</option>
</select>
Upvotes: -1
Reputation: 4622
Your initial version is not working since your selector select.find("option")
returns a jQuery object known as the "wrapped set", which is an array-like structure that contains all the selected DOM elements. This elements are not jQuery objects so attr()
method will not work and that is why you get TypeError: item.attr is not a function
.
UPDATE: For @Liam, this will work with .attr('disabled', false)
as you can see from the code below. But I still prefer using .prop()
.
var select = $("#selectId");
select.find("option").each(function(index, item) {
$(item).attr('disabled', false);
});
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="selectId">
<option value="JavaScript" disabled="">JavaScript</option>
<option value="Angular">Angular</option>
<option value="Backbone" disabled="">Backbone</option>
</select>
Upvotes: 1
Reputation: 15565
var select = $("#selectId");
select.find("option:disabled").prop("disabled",false)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="selectId">
<option value="JavaScript" disabled="">JavaScript</option>
<option value="Angular">Angular</option>
<option value="Backbone" disabled="">Backbone</option>
</select>
:disabled
to select all disabled.prop()
to set to enabledUpvotes: 2