CODEWITHSUNDEEP
javaregexstring
Maya Sela
Maya Sela

Reputation: 39

How to validate that there are no spaces between two characters in a string, using regex

I am trying to validate that there NO spaces between two characters (or in the middle of a name) in a string.

I want a regex that will accept " ab " and reject " a b " .

I tried using "\\s*((_[a-zA-z]+)|([a-zA-Z]+[a-zA-Z0-9]*))\\s*" and "(\\s*\\S\\s*)" .

p.s I don't care about spaces before and after the character\word.

Thanks in advance!

Upvotes: 1

Views: 2725

Answers (3)

garyh
garyh

Reputation: 2852

Try ^\s*\w+\s*$

This looks for zero or more spaces then any word characters [a-z0-9_] then zero or more spaces again before the end of the string

See demo

Upvotes: 1

Pavneet_Singh
Pavneet_Singh

Reputation: 37404

you can use \\s*\\S+\\s*`

  • \\s* match zero or more spaces
  • \\S+ match one or more non-space characters

  • \\s* match zero or more spaces

    System.out.println(" aa ".matches("\\s*\\S+\\s*")); // true
System.out.println(" a bc ".matches("\\s*\\S+\\s*")); // false

Note : matches implicitly include starting of match ^ and ending of match $ anchors and there is no need of capturing group () unless you are trying to fetch the specified match out of your data.

To match only alphabets use \\s*[a-zA-Z]+\\s*

Upvotes: 2

user1919238
user1919238

Reputation:

You can match exactly N characters with {N}

So, you can just use:

\\S{2}

which matches any two non-whitespace characters; or

\\w{2}

which matches two word characters. 

 [a-zA-Z]{2}

two letters, etc.

Upvotes: 0

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