CODEWITHSUNDEEP
regexbashshellsed
Dusty
Dusty

Reputation: 129

Sed with wildcard between " "

I have some file in which I need to change the logging level and trying to use sed 

    <asyncLogger name="blabla" additivity="true" level="info" includeLocation="true">
    </asyncLogger>

    <asyncLogger name="blabla1" additivity="true" level="fine">

I tired this command but it cuts down the end of the line. 

sed  's/\(level="\).*/"\1\debug\"/' file.xml

I am trying to fine level="wildcard" and replace it with level="debug" and the rest of the line

Upvotes: 1

Views: 272

Answers (3)

dawg
dawg

Reputation: 104024

It is almost never a good idea to modify xml with sed...

That said, your issue is the .* since it is greedy. It sucks up the remainder of the line.

You can do:

$ sed -E 's/(level=")[^"]*/\1debug/' file
<asyncLogger name="blabla" additivity="true" level="debug" includeLocation="true">
</asyncLogger>

<asyncLogger name="blabla1" additivity="true" level="debug">

Upvotes: 2

Ahmed Masud
Ahmed Masud

Reputation: 22402

Something like this should replace level="blah" with level="debug"

  sed -e 's/level="[^"]"/level="debug"/g' file.xml

Upvotes: 0

Gilbert
Gilbert

Reputation: 3776

You need to make the regular expression less greedy as your .* eats everything to the end of the line.

sed -r -e 's/(\<level *= *)["a-zA-Z"]+/\1"debug"/g'

Upvotes: 0

Related Questions