CODEWITHSUNDEEP
python
Steven
Steven

Reputation: 609

Python NameError 'Y' not found

I was trying to make a program that generate a number within range of 1-6 randomly. And will stop when the user input 'N'

Here is my code

import random
def roll():
    min = 1
    max = 6
    value = random.randrange(min,max+1)
    print(value)

x = 'Y'
while (x == 'Y'):
    roll()
    x = chr(input("again?(Y/N)"))

and this is the error message

Traceback (most recent call last): File "Dice.py", line 11, in x = chr(input("again?(Y/N)")) File "", line 1, in NameError: name 'Y' is not defined

Upvotes: 0

Views: 89

Answers (4)

Stack
Stack

Reputation: 4526

change your code to use str instead of chr

chr() : Return a string of one character whose ASCII code is the integer i. For example, chr(97) returns the string 'a'. The argument must be in the range [0..255]

import random
def roll():
    min = 1
    max = 6
    value = random.randrange(min,max+1)
    print(value)

x = 'Y'
while (x == 'Y'):
    roll()
    x = input("again?(Y/N)")    #Python 3
    x = raw_input("again?(Y/N)")  #Python 2

Upvotes: 0

user4963716
user4963716

Reputation:

Use raw_input in Python 2 to get a string, input in Python 2 is equivalent to eval(raw_input). So, When you enter something like Y in input it thinks that you're looking for a variable named Y:

import random
def roll():
    min = 1
    max = 6
    value = random.randrange(min,max+1)
    print(value)

x = 'Y'
while (x == 'Y'):
    roll()
    x = (raw_input("again?(Y/N)"))

USE raw_input() and remove chr() function

Upvotes: 1

R.A.Munna
R.A.Munna

Reputation: 1709

without typecasting in python 3.x

x = input("again?(Y/N)")

Upvotes: 0

Steven
Steven

Reputation: 609

this works thank you

import random
def roll():
    min = 1
    max = 6
    value = random.randrange(min,max+1)
    print(value)

x = 'Y'
while (x == 'Y'):
    roll()
    x = raw_input("again?(Y/N)")

Upvotes: 0

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