CODEWITHSUNDEEP
javatomcatservlets
user7328234
user7328234

Reputation: 413

How does servlet handle multiple uploaded files in one request

I know how to save it when only one file is uploaded in servlet.
HTML

<form action="storeArticle" method="post" enctype="multipart/form-data">
    <input type="file" name="file">
    ...
</form>

Servlet can save the uploaded file as follows: 

Part part = request.getPart("file");
File file = new File(filePath);
try (InputStream inputStream= part.getInputStream()) { // save uploaded file
    Files.copy(inputStream, file.toPath());
}

For example, in https://stackoverflow.com/questions/ask, user can choose uploading multiple images by clicking the only one image icon.But when multiple files are uploaded one time, how can servlet save these uploaded files?
HTML

<input type="file" name="file[]" multiple >

Upvotes: 0

Views: 903

Answers (1)

tapsey
tapsey

Reputation: 454

<form action="storeArticle" method="post" enctype="multipart/form-data">
<input type="file" name="file">
<input type="file" name="file2">
<input type="file" name="file3">

</form>

The servlet does this

Part part = request.getPart("file");
 File file = new File(filePath);
 try (InputStream inputStream= part.getInputStream()) { // save uploaded file
  Files.copy(inputStream, file.toPath());
 }


  Part part = request.getPart("file2");
  File file = new File(filePath);
 try (InputStream inputStream= part.getInputStream()) { // save uploaded file
  Files.copy(inputStream, file.toPath());
 }



  Part part = request.getPart("file3");
  File file = new File(filePath);
  try (InputStream inputStream= part.getInputStream()) { // save uploaded file
    Files.copy(inputStream, file.toPath());
   }

Upvotes: 1

Related Questions