CODEWITHSUNDEEP
javascriptpromise
Kumar KS
Kumar KS

Reputation: 953

Promise does not resolve to true or false

export const checkLoggedIn = () => {
  return new Promise((resolve, reject) => {
    apiConfig.fetchApi('/users/is_valid', {}, 'get', {})
    .then((resp)=> {
        resolve(true);
    })
    .catch((exception)=> {
        reject(false);
    })
    .done()
  })
}

Above is my user token checking code. But function checkLoggedIn() is giving like the below image enter image description here

But I want to get true or false only. Please if you find the issue in code, comment it out

Upvotes: 1

Views: 786

Answers (1)

Andru
Andru

Reputation: 6184

Please check the definitions of then and catch and the general definition and usage of a Promise.

It seems that in your example apiConfig.fetchApi returns a Promise (because you're using then() which works on a Promise). Thus you don't have to create a new Promise.

Your code could look like this (I excluded the response parameter here because you don't use it in your code snippet):

export const checkLoggedIn = () => (
  apiConfig.fetchApi('/users/is_valid', {}, 'get', {})
    .then(() => true)
    .catch(error => { console.log(error); return false; })
);

If apiConfig.fetchApi does not return a Promise, you can create a Promise. But then you have to work with the return value of apiConfig.fetchApi and resolve or reject depending on its value.

Upvotes: 3

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