Reputation: 1
This is my dao method in which i try to get user details from database :
public UserInfo findUserInfo(String userName) {
String sql = "Select new " + UserInfo.class.getName() + "(u.username,u.password) "//
+ " from " + User.class.getName() + " u where u.username = :username ";
Session session = sessionFactory.getCurrentSession();
Query query = session.createQuery(sql);
query.setParameter("username", userName);
return (UserInfo) query.uniqueResult();
}
And when i try to execute it i get this error :
Caused by: org.hibernate.QueryParameterException: could not locate named parameter [username]
at org.hibernate.engine.query.spi.ParameterMetadata.getNamedParameterDescriptor(ParameterMetadata.java:148)
at org.hibernate.engine.query.spi.ParameterMetadata.getNamedParameterExpectedType(ParameterMetadata.java:165)
at org.hibernate.internal.AbstractQueryImpl.determineType(AbstractQueryImpl.java:523)
at org.hibernate.internal.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:493)
at org.spajic.stefan.springhibernatesecurity.dao.UserInfoDAO.findUserInfo(UserInfoDAO.java:33)
at org.spajic.stefan.springhibernatesecurity.dao.UserInfoDAO$$FastClassBySpringCGLIB$$c14aad39.invoke(<generated>)
at org.springframework.cglib.proxy.MethodProxy.invoke(MethodProxy.java:204)
at org.springframework.aop.framework.CglibAopProxy$CglibMethodInvocation.invokeJoinpoint(CglibAopProxy.java:717)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:157)
at org.springframework.transaction.interceptor.TransactionInterceptor$1.proceedWithInvocation(TransactionInterceptor.java:99)
at org.springframework.transaction.interceptor.TransactionAspectSupport.invokeWithinTransaction(TransactionAspectSupport.java:281)
at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:96)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:179)
at org.springframework.aop.framework.CglibAopProxy$DynamicAdvisedInterceptor.intercept(CglibAopProxy.java:653)
at org.spajic.stefan.springhibernatesecurity.dao.UserInfoDAO$$EnhancerBySpringCGLIB$$3fdca957.findUserInfo(<generated>)
at org.spajic.stefan.springhibernatesecurity.authentication.MyUserDetailsService.loadUserByUsername(MyUserDetailsService.java:25)
at org.springframework.security.authentication.dao.DaoAuthenticationProvider.retrieveUser(DaoAuthenticationProvider.java:114)
... 36 more
And here is User class and UserInfo class as well. User is hibernate entity and UserInfo is model that i use.
@Entity
@Table(name = "Users")
public class User {
private String username;
private String password;
private boolean enabled;
@Id
@Column(name = "username", length = 36, nullable = false)
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
@Column(name = "password", nullable = false)
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
@Column(name = "enabled", nullable = false)
public boolean isEnabled() {
return enabled;
}
public void setEnabled(boolean enabled) {
this.enabled = enabled;
}
}
public class UserInfo {
private String userName;
private String password;
public UserInfo() {
}
// Do not change this constructor, it used in hibernate Query.
public UserInfo(String userName, String password) {
this.userName = userName;
this.password = password;
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
}
Any help ?
Upvotes: 0
Views: 1784
Reputation: 881
Hope this helps , query accept even positional parameters :
maybe you can try u.username = ?1
in query
and query.setParameter(1, userName);
setting parameter
Anyway you can get the result to the User object and use that , i think you don't need UserInfo .
Upvotes: 0
Reputation: 580
Looks like the property is named UserInfo:userName in your POJO and your are trying to use username
I mean you are using a small 'n' instead of a caps 'N'
Upvotes: 2