Reputation: 633
I am using the for-loop below:
console.log(a1);
for(var f = 0; f < a1.length; f++){
b= a1[f];
console.log(b);............
My console shows me this:
Array [ Array[6], Array[8] ]
Array [ Object, Object, Object, Object, Object, Object ]
Array [ Object, Object, Object, Object, Object, Object, Object, Object]
Now, the first Array line in the console is console.log(a1)
and the other 2 Arrays are console.log(b)
.
I want to get access to the whole first Array of console.log(b)
only.
I tried to use console.log(b[0]), but this shows me only the first objects including their properties of the 2 Arrays, but I want to see the full first Array with the 6 elements only on my console. Can someone help me to solve?
Upvotes: 0
Views: 80
Reputation: 599
As I understand you want to work with the first array of objects, which is the first element of a1
, so you need to loop through a1[0]
which gives you the first array as wanted:
for(var f = 0; f < a1[0].length; f++) {
var b = a1[0][f];
console.log(b);
//do stuff here
}
Upvotes: 1