CODEWITHSUNDEEP
javascript
mdmb
mdmb

Reputation: 5283

Sort array of object based on another array

So let's say I have an array:

const chunks = [
    {id: 0, names: ['app']}, 
    {id: 1, names: ['contact']}, 
    {id: 2, names: ['bootstrap']}
];

And I want it to be sorted based on the names property, so the order is like in this array:

const original = ['bootstrap', 'app', 'contact'];

What is the most efficient way to do this?

Upvotes: 0

Views: 310

Answers (3)

Nina Scholz
Nina Scholz

Reputation: 386816

You could use the delta of the indices of names in original.

const chunks = [{ id: 0, names: ['app'] }, { id: 1, names: ['contact'] }, { id: 2, names: ['bootstrap'] }],
    original = ['bootstrap', 'app', 'contact'];

chunks.sort((a, b) => original.indexOf(a.names[0]) - original.indexOf(b.names[0]));

console.log(chunks);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 1

cheesenthusiast
cheesenthusiast

Reputation: 139

Easy way: convert chunks into an object so you get the correct one with just the key, then map over the (already sorted) array to plug in the object in place.

cMap = chunks.reduce((p,c) => Object.assign( p, {[c.names[0]]: c} ), {});
const sorted = original.map(k => cMap[k]);

Upvotes: 1

Vladimir Gordienko
Vladimir Gordienko

Reputation: 3470

Try this method: 

const chunks = [{id: 0, names: ['app']}, {id: 1, names: ['contact']}, {id: 2, names: ['bootstrap']}];
const original = ['bootstrap', 'app', 'contact'];
let result = [];
for(let i = 0; i < original.length; i++) {
    for(let j = 0; j < chunks.length; j++) {
        if(chunks[j].names.indexOf(original[i]) !== -1) {
            result.push(chunks[j]);
        }
    }
}
console.log(result);

Upvotes: 1

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