Reputation:
I want to make the word: 'error' repeat itself numerous times. This is an easy task in itself, but I do not know how to print them one at a time, at whatever speed I choose. I understand that my question has been partially covered, but I do not wish for the previous word of the string to dissapear.
print('Error! ' *20)
The output that I want is Error! Error! (each released individually instead of being released all at once.)
How can I make it so that python does not release all of the string at the same time? It would also be good to know whether I can make it print in columns, but still along the widths.
Upvotes: 0
Views: 134
Reputation: 402363
import time
for _ in range(20):
print('Error!', end=' ', flush=True) # flush courtesy inspectorG4dget to disable buffering
time.sleep(0.2)
This'll print 'Error!' every 200 milliseconds on the same line (...20 times). Change that for
to a while
for better control over the stopping condition.
Upvotes: 1
Reputation: 1936
import time
for i in range(20):
print ("Error!")
time.sleep(60) #pause for one minute
You can use a for loop to choose the number of times to print, and sleep()
from the time library to do the pausing.
Upvotes: 0
Reputation: 113915
This will print Error!
20 times (on 20 lines/rows), over a duration of 20 seconds
import time
for _ in range(20):
print("Error!")
time.sleep(1) # change 1 to whatever number you want, to control the amount of time before "Error!" is printed again
This will print "Error!" 20 times on the same line (20 columns) over a duration of 20 seconds:
import time
for _ in range(20):
print("Error!", end='', flush=True)
time.sleep(1) # change 1 to whatever number you want, to control the amount of time before "Error!" is printed again
Upvotes: 1