CODEWITHSUNDEEP
pythonarrayslistdictionary
newbie1239
newbie1239

Reputation: 35

Convert array to list by using dictionary

if you have an array, and you want to convert it by using your defined dictionary, how do you do? input:

my_dict = {1 : 'J',2:'F', 3:'M',4: 'A',5: 'M',6 : 'J',7:'J', 8:'A',9: 'S',10: '0',11 : 'N',12:'D'}
x=np.array(2,6,8,1,.....)

output:

y=("F","J","A","J",.....)

We have tried this:

my_dict = {1 : 'J',2:'F', 3:'M',4: 'A',5: 'M',6 : 'J',7:'J', 8:'A',9: 'S',10: '0',11 : 'N',12:'D'}
a = np.empty(len(x))
for i in range(0,len(x)):
    b=my_dict[x[i,0]]
    a[i,0]=b

Upvotes: 1

Views: 70

Answers (3)

Sid
Sid

Reputation: 146

dict.get() won't throw KeyNotFoundError exception if the key doesn't exist.

my_dict = {1 : 'J',2:'F', 3:'M',4: 'A',5: 'M',6 : 'J',7:'J', 8:'A',9: 'S',10: '0',11 : 'N',12:'D'}

# With KeyNotFoundError handled
x=[my_dict.get(i) for i in [2,6,8,1,10,11]]

Upvotes: 0

Sid
Sid

Reputation: 146

Dont know why numpy but this code will work:

my_dict = {1 : 'J',2:'F', 3:'M',4: 'A',5: 'M',6 : 'J',7:'J', 8:'A',9: 'S',10: '0',11 : 'N',12:'D'}
x=[2,6,8,1,10,11]

result=[]
for key in  x:
    result.append(my_dict[key]);

print(result)

Upvotes: 0

e4c5
e4c5

Reputation: 53744

Why you are using numpy here is beyond me and please note that your numpy arrange initialization syntax is incorrect. But you said output that looks like

 ("F","J","A","J",.....)

for that you need something like:

import numpy as np
my_dict = {1 : 'J',2:'F', 3:'M',4: 'A',5: 'M',6 : 'J',7:'J', 8:'A',9: 'S',10: '0',11 : 'N',12:'D'}
x=np.array([2,6,8,1,10,11])

[my_dict[i] for i in x]

Upvotes: 2

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