CODEWITHSUNDEEP
xmlxsltxslt-1.0
tradersjoe
tradersjoe

Reputation: 37

Strip a tag in XML using XSLT

<Tag1>
<dummy><name>qwert</name><id>123</id></dummy>
<dummy><name>wert</name><id>023</id></dummy>
<dummy><name>hfj</name><id>103</id></dummy>    
</Tag1>

I have above XML for which I want to strip the in the XML output file

Desired O/p:

<Tag1>
<name>qwert</name><id>123</id>
<name>wert</name><id>023</id>
<name>hfj</name><id>103</id>   
</Tag1>

Also I tried using the below XSLT

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="node()|@*">
 <xsl:copy>
 <xsl:apply-templates select="node()|@*"/>
 </xsl:copy>
 </xsl:template>

 <xsl:template match="dummy"/>
 </xsl:stylesheet>

It's removing as well everything underneath it

Upvotes: 1

Views: 131

Answers (1)

Tim C
Tim C

Reputation: 70608

You need to do this instead, to ensure the children of dummy are still selected

 <xsl:template match="dummy">
   <xsl:apply-templates />
 </xsl:template>

EDIT: Here is the complete spreadsheet

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" omit-xml-declaration="yes" />

  <xsl:template match="node()|@*">
    <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="dummy">
    <xsl:apply-templates />
  </xsl:template>
</xsl:stylesheet>

Upvotes: 1

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