CODEWITHSUNDEEP
pythonregexpython-3.x
DarkSuniuM
DarkSuniuM

Reputation: 2582

Extract substring with Regex on Python 3

I'm trying to extract a substring with Regex,

Here is my script:

import re
_text = "sdiskpart(device='D:\\', mountpoint='D:\\', fstype='FAT32', opts='rw,fixed')"
print(re.findall("device=(\\'.*\\')", _text))

I'm trying to get the value of device, in this string it's "D:\"

as u can see I tried "device=(\'.*\')" with REgex and it returned:

["'D:\', mountpoint='D:\', fstype='FAT32', opts='rw,fixed'"]

I'm not professional on REgex, How can I force it to take D:\ and print it out ?

Upvotes: 0

Views: 5507

Answers (2)

Yoav Glazner
Yoav Glazner

Reputation: 8066

You can use non-eager regexp

import re

print( re.findall("device='(.*?)'", _text))

notice that the .*? means non-eager so it will take the least chars until the next ' ...

Upvotes: 4

Anoop Toffy
Anoop Toffy

Reputation: 916

REFER https://docs.python.org/3/library/re.html

>>> print(re.findall("device=(\\'[A-Z]:\\\\')", _text))
["'D:\\'"]

You might have to replace * with [A-Z]. I think the drive letter are in caps always else use[A-Za-z]

Upvotes: 2

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