Reputation: 141
Suppose I have nested classes as follows defined in a header file:
class ClassA
{
private:
class ClassB
{
private:
int member_b;
public:
void function_name();
};
};
In order to give a definition to the function "function_name()" in an external .cpp file, I have to access it like this:
void ClassA::ClassB::function_name()
{
std::cout << member_b;
return;
}
For the sake of this example, please do not ask why I'm using nested classes; I have a reason for doing so in my actual project. However, my question is this; is it possible to somehow shorten the ClassA::ClassB::function_name()
in the implementation file to something like short::function_name()
while still keeping the classes nested? I don't think that typedefs or new namespace definitions can help me here, but maybe I'm wrong.
Upvotes: 2
Views: 537
Reputation: 916
Qualified type names allow you to define a typedef to represent a qualified class name. You can then use the typedef with the :: (scope resolution) operator to refer to a nested class or class member, as shown in the following example:
class outside
{
public:
class nested
{
public:
static int x;
static int y;
int f();
int g();
};
};
int outside::nested::x = 5;
int outside::nested::f() { return 0; };
typedef outside::nested outnest; // define a typedef
int outnest::y = 10; // use typedef with ::
int outnest::g() { return 0; };
However, using a typedef to represent a nested class name hides information and may make the code harder to understand.
Upvotes: 1
Reputation: 470
Have you tried using aliases?
// C++11
using fmtfl = std::ios_base::fmtflags;
// C++03 equivalent:
// typedef std::ios_base::fmtflags fmtfl;
fmtfl fl_orig = std::cout.flags();
fmtfl fl_hex = (fl_orig & ~std::cout.basefield) | std::cout.showbase | std::cout.hex;
// ...
std::cout.flags(fl_hex);
Code source: https://msdn.microsoft.com/en-us/library/dn467695.aspx
Upvotes: 0