Reputation: 77
I'm trying to get Total(Sum) of a property of "df" object.I have attached screen shot of sample database I'm using
I tried to get the graph using following query
MATCH P= (n:Org)-[:O_CH*0..]->()-[:LEAF*0..]->()-[:CH*0..]->()-[:FOR*0..]->() RETURN P
To create objects
create(n:Org{name:'Root',id:1})
create(n:Org{name:'L1.1',id:2,parent:1})
create(n:Org{name:'L1.2',id:3,parent:1})
create(n:Org{name:'L1.3',id:4,parent:1})
create(n:Org{name:'L2.1',id:5,parent:3})
create(n:Org{name:'L2.2',id:6,parent:4})
create(n:Op{name:'CH1',id:7,orgId:5})
create(n:Op{name:'CH2',id:8,orgId:5 ,parent:'CH1'})
create(n:Proj{name:'P1',id:9,opp:'CH2'})
create(n:Proj{name:'P2',id:10,opp:'CH1'})
create(n:R{name:'R1',id:200,orgId:2 })
create (n:df{id:100,map:8,forecast:toFloat(10)})
create (n:df{id:101,map:7,forecast:toFloat(10)})
create (n:df{id:102,map:9,forecast:toFloat(10)})
create (n:df{id:103,map:10,forecast:toFloat(10)})
create (n:df{id:104,map:200,forecast:toFloat(10)})
To Crate relationships
MATCH (c:Org),(p:Org) WHERE c.parent = p.id create (p)-[:O_CH]->(c)
MATCH (c:Op),(p:Op) WHERE c.parent = p.name create (p)-[:CH]->(c)
MATCH (c:Op),(p:Org) WHERE c.orgId = p.id create (p)-[:LEAF]->(c)
MATCH (c:Proj),(p:Op) WHERE c.opp = p.name create (p)-[:CH]->(c)
MATCH (c:R),(p:Org) WHERE c.orgId = p.id create (p)-[:LEAF]->(c)
MATCH (c:df),(p:) WHERE c.map = p.id create (p)-[:FOR]->(c)
I'm expecting 60 as total where I get 260 as total. Please let me know where I'm wrong . Need your help to figure out.
Upvotes: 2
Views: 792
Reputation: 16365
I'm trying to get Total(Sum) of a property of "df" object.
I believe you needs a simple query that match all nodes with label :df
and return the sum of node.forecast
. Try it:
// Match all nodes with :df label
MATCH(n:df)
// Return the sum of the property 'forecast' of each matched node
RETURN sum(n.forecast)
From comments:
Thank you Bruno.But the thing i need to get the aggregated value as a example if i select L2.1 , i need to get the sum of df objects which are under that node
This should work:
MATCH({name:'L2.1'})-[*]->(n)
RETURN SUM(n.forecast)
Upvotes: 1