CODEWITHSUNDEEP
mysqlsql
Luke
Luke

Reputation: 25

Selecting lowest value of grouped column

A         B        C
+--------+-------+----+
|    310 | 09001 | 18 |
|  80614 | 09001 | 18 |
| 169009 | 09001 | 19 |
| 201695 | 09001 | 19 |
| 282089 | 09001 | 19 |
| 320438 | 09001 | 19 |
| 131733 | 09001 | 19 |
| 387427 | 09001 | 19 |
| 404201 | 09001 | 19 |
| 525449 | 09001 | 19 |
| 605542 | 09001 | 19 |
| 710740 | 09001 | 18 |
| 746380 | 09001 | 19 |
| 867492 | 09001 | 19 |
| 864637 | 09005 | 18 |
| 710741 | 09005 | 17 |
| 746375 | 09005 | 18 |
| 556470 | 09005 | 18 |
| 604258 | 09005 | 18 |
| 401597 | 09005 | 18 |
| 141331 | 09005 | 18 |
| 336054 | 09005 | 18 |
| 387423 | 09005 | 18 |
| 203706 | 09005 | 18 |
| 278651 | 09005 | 18 |
| 126352 | 09005 | 18 |
|    312 | 09005 | 17 |
|  74627 | 09005 | 17 |
+--------+-------+----+

Wasnt sure how to title the question, but here's the scenario. Im looking to display 1 row for each distinct value in column B, Which is the highest value in column C, and the lowest in Column A.

For example, for 09001 It would be 169009 09001 19, and for 09005 it would display 126352 09005 18

So basically max of column C grouped by column B, and lowest value in column A of those rows.

Thanks in advance

SELECT MIN(A) AS MaxA, B, MAX(C) AS MinC FROM Table GROUP BY B

gives 

310 09001   19
312 09005   18

not 

131733 09001 19
141331 09005 18

which is what I need

select min(A), B, C from my_table where ( C) in ( select max(C) from my_table where B in (09001,09005) group by B) and B in (09001,09005) group by B, C

results in

310 09001 18

126352 09005 18

131733 09001 19

but there should only be one result for 09001

Select min A,B from my_table where C in (select max(c) from my table where A in (09001, 09005)group by A) and fips in (09001, 09005) group by A

ended up working, although it only shows A and B, but all I need is A for this example. Im sure there are other ways to get C to show as well.

Thanks for the help guys

Upvotes: 0

Views: 51

Answers (2)

Dan Truitt
Dan Truitt

Reputation: 107

I think you've already solved your own problem.

SELECT MIN(A) AS MaxA, B, MAX(C) AS MinC
FROM Table
GROUP BY B

Unless I made some sort of silly error there.

EDIT: I understand the requirements better now. Give this a shot.

WITH T1 AS (
SELECT B, MAX(C) AS MaxC
FROM Table
GROUP BY B
), T2 AS (
SELECT MIN(A) AS MinA, MaxC
FROM T1
GROUP BY MaxC)

SELECT T2.MinA AS A, T1.B, T1.MaxC AS C
FROM T1
INNER JOIN T2
ON T1.MaxC = T2.MaxC

Upvotes: 1

ScaisEdge
ScaisEdge

Reputation: 133410

could you need min over the max for B 

  select  min(A), B, C
  from my_table 
  where ( B, C ) in (
    select B, max(C)
    from my_table 
    group by B
  )
 group by B,C

Upvotes: 0

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