CODEWITHSUNDEEP
javascriptregex
CyberLX
CyberLX

Reputation: 275

Regex match one occurrence of a character while matching 2 of another

As the question says, I'm trying to match one occurrence of a character and at the same time 2 occurrences of another. For example, in the string "_Hell_o" I would like to match the first "_" there and in the case of "++Hello" I would like to match exactly both "+". Basically a function like this:

function change(str){
    console.log(str.replace(/[_+{2}]/, ''));

change("++Hello");
change("_Hello");
change("+Hello");

And the outputs to be

>>> Hello
>>> Hello
>>> +Hello

But that function does not work

Upvotes: 1

Views: 398

Answers (3)

cs95
cs95

Reputation: 403218

/^_{1}|\+{2}/g does the trick.

function change(str){
    console.log(str.replace(/^_{1}|\+{2}/g, ''));
}

change("++Hello");
change("+++Hello");
change("_Hell__o");
change("___Hello");
change("+Hello");

Upvotes: 4

David Knipe
David Knipe

Reputation: 3444

str.replace('++', '').replace('_', '')

Simplified version of the answer by YCF_L. Like YCF_L's answer, it will remove the first occurrence of ++ (if any) and the first occurrence of _ (if any).

Upvotes: 0

Youcef LAIDANI
Youcef LAIDANI

Reputation: 60046

You can solve your problem using two replace for example :

var array = ["++Hello", "_Hello", "+Hello"];
for (var i = 0; i < array.length; i++) {
    console.log(array[i].replace(/\+{2}/, '').replace(/_(.*)/, '$1'))
}

Upvotes: 3

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