CODEWITHSUNDEEP
pythonpython-3.x
Holy
Holy

Reputation: 37

Iterating through a dictionary to find the most frequently used word

I made a quick bit of code that checks a list of input words by the user and counts how many of the same word the user has typed. if print is input it is supposed to print the most frequent word used as well as how many times it was used for example The word 'Hello' has been used '12' times i am just not sure how to get it to iterate through the dictionary and find the most frequent word

Here is the code

d = {}
L2 = []
Counter = 0
checker = -1

while True:
    Text = str(input('enter word '))
    Text = Text.lower()

if Text in ['q', 'Q']:
    break

if Text in ['Print', 'print']:
    for word in L2:
        if word not in d: 
            counter = L2.count(word)
            d[word] = counter

#This part does not work
    for value in d[0]:
        if checker < value:
            checker = value
    print(checker)  

#This part does         
L2.append(Text)

Upvotes: 0

Views: 138

Answers (1)

Gahan
Gahan

Reputation: 4213

d = {}
L2 = []

while True:
    text_input = input('enter word ') # input by default stores values in string format
    text_input = text_input.lower()

    if text_input == 'q': # you have used text_input.lower() so you don't need to use it is 'q' or 'Q' it will never be 'Q'
        break

    elif text_input == 'print':
        for item in set(L2): # set(L2) will only keep unique values from list L2
            d[item] = L2.count(item)  # counts for all unique items and append it to dictionary
        for word, count in d.items(): # by using this loop you can print all possible max values i.e. if two word has same max occurance it will print both
            if count == max(d.values()):
                print("Word : {} repeated {} times.".format(word, count))

    else:      
        L2.append(text_input) # input is neither 'q' nor 'print' hence append word in list

Upvotes: 1

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