CODEWITHSUNDEEP
javascriptregexvalidationwords
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aboutus

Reputation: 239

Regex - Allow capital letters just at the beginning of words

I have to check for capital letters to exist just at the beginning of words.

My regex now looks like this: /^([A-ZÁÉÚŐÓÜÖÍ]([a-záéúőóüöí]*\s?))+$/

It's at the words beginning works good, but if the problem not at the beginning of the word it's fails. For example: John JohnJ got validated.

What should i alternate in my regex to works well?

Upvotes: 0

Views: 149

Answers (2)

oldboy
oldboy

Reputation: 5954

You can do this: /^([A-ZÁÉÚŐÓÜÖÍ]{0,1}([a-záéúőóüöí]*\s?))+$/

With {a,b}, a is the least amount of characters it will match, whereas b is the most amount of characters it will match.

If there is ALWAYS going to be a capital letter at the beginning, instead you can simply use: /^([A-ZÁÉÚŐÓÜÖÍ]{1}([a-záéúőóüöí]*\s?))+$/

In this preceding case, {c}, c is the exact number of characters it will match.

Here is a resource with good information.

Upvotes: 0

Sebastian Proske
Sebastian Proske

Reputation: 8413

In your regex pattern the space is optional, allowing combinations like JJohn or JohnJ - the key is to make it required between words. There are two ways to do this:

Roll out your pattern:

/^[A-ZÁÉÚŐÓÜÖÍ][a-záéúőóüöí]*(?:\s[A-ZÁÉÚŐÓÜÖÍ][a-záéúőóüöí]*)*$/

Or make the space in your pattern required, but alternatively allow it to be the end of line (this allows a trailing space though).

/^(?:[A-ZÁÉÚŐÓÜÖÍ][a-záéúőóüöí]*(?:\s|$))+$/

In both patterns I have removed some superfluous groups of your original and turned all groups into non-capturing ones.

Upvotes: 1

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