CODEWITHSUNDEEP
pythondjango
Rock Hill
Rock Hill

Reputation: 149

TypeError: f0() takes 1 positional argument but 9 were given

Suppose i have a list:

a=['hello.com','ok.com']

i have two function:

   def f0(id):
         try:
             model.objects.get(links=id)
         except:
             model(modelfield=id).save()

   def f1(request):
        for i in a:
             t1=thread.Thread(target=f0,args=(i))
             t1.start()

While i try to run this on my server , its giving me error .

  TypeError: f0() takes 1 positional argument but 9 were given

Kindly tell me whats the problem .

Upvotes: 3

Views: 3646

Answers (2)

Fred
Fred

Reputation: 76

In 'args=(i)', (i) is not a tuple. Convert (i) into a tuple by appending , so the right statement will be: t1=thread.Thread(target=f0,args=(i,))

Upvotes: 0

Martijn Pieters
Martijn Pieters

Reputation: 1123930

You are passing in a single string as the args value:

args=(i)

That's not a tuple, that's a grouped expression containing just 'hello.com', an iterable with 9 separate elements (single-character strings).

Add a comma; tuples are formed by the comma, not the parentheses (although you need parentheses to disambiguate the tuple from other arguments in a call):

args=(i,)

or if you find that confusing, use a list:

args=[i]

Upvotes: 8

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