CODEWITHSUNDEEP
regexpowershellpowershell-2.0
Sumith Chalil
Sumith Chalil

Reputation: 358

Comparing installed and current versions

I want to get installed versions and current versions from a log file and I have got the output by using the following commands:

$versions = Select-String -Path $path -Pattern "Comparing product versions" |
            % { $_.Line.Split() }

$installed = $versions[6]
$installed = echo "$installed".Trim(",")
$current   = $versions[7]

The problem is: I don't want hardcoding. Is there any method like regex to replace this and to get installed version and current version seperately.

This is what the relevant log line looks like:

ISS_LOG [14:45:36]: Comparing Product Versions - Installed[1.2.0.10], Current[1.2.0.10]

Trying the 1st solution, I get an error: Error - cannot index into null array

Upvotes: 1

Views: 75

Answers (1)

G42
G42

Reputation: 10019

You can use the regex strings Installed\[(.*)\], and Current\[(.*)\], assuming the pattern is that you have installed/current followed by square brackets with the version number.

This returns groups with a full match (not what you want) and match for what's int he square brackets (what you want). More regex explanation

In Code:

$myString = "ISS_LOG [14:45:36]: Comparing Product Versions - Installed[1.2.0.10], Current[1.2.0.10]"

$installedRegex = "Installed\[(.*)\],"
$currentRegex   = "Current\[(.*)\]"

$installedVersion = $([regex]::Matches($myString,$installedRegex)).Groups.value[1]
$CurrentVersion   = $([regex]::Matches($myString,$currentRegex)).Groups.value[1]

Output On PowerShell 5.1

Edit - PowerShell 2.0 version

$installedVersion = $([regex]::Matches($myString,$installedRegex)).Groups[1].value
$CurrentVersion   = $([regex]::Matches($myString,$currentRegex)).Groups[1].value

Upvotes: 2

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