CODEWITHSUNDEEP
javaandroidandroid-api-levels
Alex Ioja-Yang
Alex Ioja-Yang

Reputation: 33

Create Color from rgb Stringin Java

This is my code to convert a String to Color: 

public Color prepareColour(String str) {
    str.replace("#", "");
    float r = Float.valueOf(str.substring(0,1));
    float g = Float.valueOf(str.substring(2,3));
    float b = Float.valueOf(str.substring(4,5));
    Color color = Color.valueOf(r,g,b);
    return color;

}

I get the following debug error:

Error:(16, 23) error: constructor Color in class Color cannot be applied to given types; required: no arguments found: float,float,float reason: actual and formal argument lists differ in length

However, the suggestion before compiling from Android Studio is:

Call requires API level 26 (current min is 17) ......

I see there are answers from 2011 supporting this way of creating a Color, so surely it works on API 17 and doesn't require 26.

I have tried cleaning and rebuilding the project, as well as replacing the str.substring with actual values and nothing changes.

Why will the code not compile?

Upvotes: 3

Views: 10116

Answers (2)

Submersed
Submersed

Reputation: 8870

Have you tried using Color.rgb(r,g,b) instead of Color.valueOf(...)? Color.valueOf(...) is a very new method in the Android Developer O preview, so it will only be useful on 1 API level at the moment.

Also, make sure you're using ints in the range of 0-255, or floats in the range of 0-1.

Upvotes: 9

Star_Man
Star_Man

Reputation: 1091

You can use this code.

Color.parseColor(String strColor);

This is a static method of Color class

public static int parseColor (String colorString)

https://developer.android.com/reference/android/graphics/Color.html#parseColor(java.lang.String)

Upvotes: 2

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