How do I create a diagonal border in React Native?

Question

I'm working on building a React Native app based on designs from our designer. The design has several places where there are buttons or shapes with one diagonal line (see the following example). I've tried using SkewX but that just seems to rotate the whole shape (and doesn't seem to work on Android anyway). How can I draw a rectangle/button with a diagonal border on one side?

Answer 1

You can apply css to View class and create the desired output, Heres a small demo code edited version

import React, { Component } from 'react';
import { View, StyleSheet } from 'react-native';
import { Constants } from 'expo';

export default class App extends Component {
  render() {
    return (
      <View style={styles.container}>

        <View style={styles.triangleCorner}></View>
        <View style={styles.triangleCornerLayer}></View>
         <View style={styles.triangleCorner1}></View>

      </View>
    );
  }
}

const styles = StyleSheet.create({
  container: {
    flex: 1,
    alignItems: 'center',
    justifyContent: 'center',
    paddingTop: Constants.statusBarHeight,
    backgroundColor: '#ecf0f1',
  },triangleCorner: {
    position: 'absolute',
    top:105,
    left:0,
    width: 300,
    height: 100,
    backgroundColor: 'transparent',
    borderStyle: 'solid',
    borderRightWidth: 50,
    borderTopWidth: 80,
    borderRightColor: 'transparent',
    borderTopColor: 'gray'
  },triangleCorner1: {
    position: 'absolute',
    top:100,
    left:0,
    width: 130,
    backgroundColor: 'transparent',
    borderStyle: 'solid',
    borderRightWidth: 50,
    borderTopWidth: 90,
    borderRightColor: 'transparent',
    borderTopColor: 'green'
  },triangleCornerLayer: {
    position: 'absolute',
    top:107,
    left:0,
    width:297,
    height: 100,
    backgroundColor: 'transparent',
    borderStyle: 'solid',
    borderRightWidth: 47,
    borderTopWidth: 75,
    borderRightColor: 'transparent',
    borderTopColor: 'white'
  }
});

Result: