Reputation: 173
How can i get a list of all possible values of a list with also repeated ones?
I've tried itertools.combination_with_replacement
and itertools.permutation
but the first exclude the inverted order (such as [3, 2, 1]
) and the second exclude multiple values (such as [3, 3, 1]
).
I need something like this:
Example:
list = [1, 2, 3]
results =
[1, 1, 1]
[1, 1, 2]
[1, 1, 3]
...
[3, 1, 1]
[3, 1, 2]
[3, 1, 3]
...
What can I do in Python to achieve this? Thanks in advance.
Upvotes: 2
Views: 138
Reputation: 78564
You're looking for itertools.product
, setting the repetition to 3:
>>> from itertools import product
>>> lst = [1, 2, 3]
>>> list(product(lst, repeat=3))
[(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 2, 3), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 1), (2, 1, 2), (2, 1, 3), (2, 2, 1), (2, 2, 2), (2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3)]
Upvotes: 4