CODEWITHSUNDEEP
javajava-8timestampjava-time
rhandom
rhandom

Reputation: 1278

long timestamp to LocalDateTime

I have a long timestamp 1499070300 (equivalent to Mon, 03 Jul 2017 16:25:00 +0800) but when I convert it to LocalDateTime I get 1970-01-18T16:24:30.300

Here's my code

long test_timestamp = 1_499_070_300L;

LocalDateTime triggerTime =
                LocalDateTime.ofInstant(Instant.ofEpochMilli(test_timestamp), TimeZone
                        .getDefault().toZoneId());

Upvotes: 104

Views: 178481

Answers (7)

Gaetano Piazzolla
Gaetano Piazzolla

Reputation: 1557

Starting from JDK 8, It's also possible e to leverage on the LocalDateTime method ofEpochSeconds:

private LocalDateTime epochSecondsToLocalDate(long epochSeconds) {
    ZoneId zoneId = ZoneOffset.systemDefault();
    ZoneOffset zoneOff = zoneId.getRules().getOffset(LocalDateTime.now());
    return LocalDateTime.ofEpochSecond(epochSeconds, 0, zoneOff);
}

Or, if handling milliseconds:

private LocalDateTime epochMillisToLocalDateTime(long epochMillis) {
    ZoneId zoneId = ZoneOffset.systemDefault();
    ZoneOffset zoneOff = zoneId.getRules().getOffset(LocalDateTime.now());
    return LocalDateTime.ofEpochSecond(epochMillis / 1000,
            (int) (epochMillis % 1000) * 1000000, zoneOff);
}

This method first divides the epoch timestamp by 1000 to convert milliseconds to seconds, as LocalDateTime.ofEpochSecond expects seconds. The remainder (epochMillis % 1000) represents the milliseconds part, which is then converted to nanoseconds (by multiplying by 1000000) for the nanosecond parameter of LocalDateTime.ofEpochSecond.

Upvotes: 1

Nasib
Nasib

Reputation: 1579

SIMPLE and straight forward solution will (KOTLIN)

            val timeStamp:Long=559585985988
            val sdf = SimpleDateFormat("hh:mm:ss a - MMM dd,yyyy", Locale.getDefault())
            val tz = TimeZone.getDefault()
            val now = Date()
            val offsetFromUtc = tz.getOffset(now.time)
            val localeTimeStr = sdf.format(timeStamp + offsetFromUtc) //add the offset to get the local time from the epoch timestamp

Upvotes: 0

JamieH
JamieH

Reputation: 4859

If you are using the Android threeten back port then the line you want is this

LocalDateTime.ofInstant(Instant.ofEpochMilli(startTime), ZoneId.systemDefault())

Upvotes: 9

Razib
Razib

Reputation: 11173

Try with Instant.ofEpochMilli() or Instant.ofEpochSecond() method with it- 

long test_timestamp = 1499070300L;
LocalDateTime date =
    LocalDateTime.ofInstant(Instant.ofEpochMilli(test_timestamp ), TimeZone
        .getDefault().toZoneId());

Upvotes: 3

Juan
Juan

Reputation: 2099

You need to pass timestamp in milliseconds:

long test_timestamp = 1499070300000L;
LocalDateTime triggerTime =
        LocalDateTime.ofInstant(Instant.ofEpochMilli(test_timestamp), 
                                TimeZone.getDefault().toZoneId());  

System.out.println(triggerTime);

Result: 

2017-07-03T10:25

Or use ofEpochSecond instead: 

long test_timestamp = 1499070300L;
LocalDateTime triggerTime =
       LocalDateTime.ofInstant(Instant.ofEpochSecond(test_timestamp),
                               TimeZone.getDefault().toZoneId());   

System.out.println(triggerTime);

Result: 

2017-07-03T10:25

Upvotes: 172

Alex Roig
Alex Roig

Reputation: 1574

Your issue is that the timestamp is not in milliseconds but expressed in seconds from the Epoch date. Either multiply by 1000 your timestamp or use the Instant.ofEpochSecond().

Upvotes: 3

Akshay
Akshay

Reputation: 1161

Try with the following..

long test_timestamp = 1499070300000L;
    LocalDateTime triggerTime =
            LocalDateTime.ofInstant(Instant.ofEpochMilli(test_timestamp), TimeZone
                    .getDefault().toZoneId());

By default 1499070300000 is int if it dosen't contain l in end.Also pass time in milliseconds.

Upvotes: 6

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