CODEWITHSUNDEEP
c++boostc++11shared-ptrsmart-pointers
Puppy
Puppy

Reputation: 147054

enable_shared_from_this and inheritance

I've got a type which inherits from enable_shared_from_this<type>, and another type that inherits from this type. Now I can't use the shared_from_this method because it returns the base type and in a specific derived class method I need the derived type. Is it valid to just construct a shared_ptr from this directly?

Edit: In a related question, how can I move from an rvalue of type shared_ptr<base> to a type of shared_ptr<derived>? I used dynamic_cast to verify that it really was the correct type, but now I can't seem to accomplish the actual move.

Upvotes: 29

Views: 7724

Answers (1)

James McNellis
James McNellis

Reputation: 355387

Once you obtain the shared_ptr<Base>, you can use static_pointer_cast to convert it to a shared_ptr<Derived>.

You can't just create a shared_ptr directly from this; that would be equivalent to:

shared_ptr<T> x(new T());
shared_ptr<T> y(x.get()); // now you have two separate reference counts

Upvotes: 23

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