CODEWITHSUNDEEP
clinuxbash
user5896280
user5896280

Reputation:

Run Bash Command At X Time and Terminate for X Time

Hi im working on a simple bash coding i don't know how to accomplish this and this might be easy for you guys please help.

I have a simple program on file.sh 

#!/bin/bash

./program

This ./program is a compiled version of C program which i complied using GCC im trying to use at in bash script to execute this program for few seconds and then terminate that after x interval time and restart again.

I hope you got my point?

Example: Run file.sh for 10 sec and I'll display the result from ./program C program and then after 10 sec it will restart again.

Upvotes: 0

Views: 517

Answers (2)

al3xkr
al3xkr

Reputation: 46

You can use the sleep command. For example: exec ./program && sleep n where n is the time you want the command to sleep. If you want you could put it in a while loop inside an sh script and run it continuously.

To run it continuously until you close the terminal:

while true
do
   echo "[CTRL+C] to stop..."
   timeout 10s ./program
done

Upvotes: 0

Ljm Dullaart
Ljm Dullaart

Reputation: 4969

The answer is, if I understand correctly, a combination of sleep and timout:

while :; do
    timout 10s ./program
    # display some results
    sleep 10
done

Upvotes: 2

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