CODEWITHSUNDEEP
pythonstruct
canvas123
canvas123

Reputation: 11

struct.unpack(...) works different on x64 machine

I am trying to do key = struct.unpack('L', bytes_key)[0] where bytes_key is b'\xa6\x0b\xddE' and it works fine on my x32 machine, but whenever I am trying to execute it on x64 machine it getting me error.

Traceback (most recent call last):
File "unpacker.py", line 42, in <module> decompile(obj[1]) File "unpacker.py", line 13, in decompile f.write(decrypt_record(arg).content) File "crypt.py", line 61, in crypt.decrypt_record (crypt.c:2447) record.checksum = decrypt(record.checksum, checksum_key)
File "crypt.py", line 36, in crypt.decrypt (crypt.c:1821) key = struct.unpack('L', bytes_key)[0] struct.error: unpack requires a bytes object of length 8

Upvotes: 1

Views: 135

Answers (1)

dacuna
dacuna

Reputation: 1096

You could try using "=" before the "L":

...
struct.unpack("=L", bytes_key)[0]
...

As per the documentation, it says:

Standard size depends only on the format character; see the table in the Format Characters section. Note the difference between '@' and '=': both use native byte order, but the size and alignment of the latter is standardized.

Upvotes: 1

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