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pythoncsvdictionarylist-comprehension
briyan
briyan

Reputation: 81

How to make a dict of multiple lists in python?

I want to make a list of dicts that have the following structure,

[{'Business' : 'Attorney' , 'Website text' : '(one line from the loaded file)'}, {'Business' : 'Attorney' , 'Website text' : '(one line from the loaded file)'}, ...]

However at the moment i only have a csv file consisting of the website text.

Below i have attempted to somehow create lists of the same length as my website text file, then zip them and create a dict from that. I have been unable to find information on here when it comes to creating a dict from more that 2 lists. 

with open('attorneys text.csv') as data_file:
    attorneys = list(line for line in data_file)

website = []
business = []
classes = []
for l in range(len(attorneys)):
    website.append("Website text")

for k in range(len(attorneys)):
    business.append("Business")

for i in range(len(attorneys)):
    classes.append("Attorney")

data = dict(zip((business, classes, website, attorneys)))

I am well aware of the ugliness of the try as well...

Upvotes: 0

Views: 1194

Answers (3)

rxw
rxw

Reputation: 61

This is what i would do:

data = []

with open('attorneys text.csv') as data_file:
  for line in data_file
    row = { "Business": "Attorney", "Website text": line}
    data.append(row)

I don t know if i understood well what you want to do

Upvotes: 0

Invibsid
Invibsid

Reputation: 71

Since the only difference is the text, you can do the following:

with open('attorneys text.csv') as data_file:
    data = [{'Business':'Attorney', 'Website text':line} for line in data_file]

The 'Business':'Attorney' pair will be the same for each dictionary, while the value corresponding to 'Website text' will be the data from your file.

Upvotes: 2

Ramakanth Putta
Ramakanth Putta

Reputation: 726

You can use defaultdict

from collections import defaultdict
s = ["Business", "Attorney", "Website text"]
data = defaultdict(list)

data[s[0]].append(business)
data[s[1]].append(classes)
data[s[2]].append(website)

Upvotes: 0

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