CODEWITHSUNDEEP
scalaapache-sparkapache-spark-sqlwindow-functions
Molochdaa
Molochdaa

Reputation: 2218

Get the last element of a window in Spark 2.1.1

I have a dataframe in which I have subcategories, and want the last element of each of these subcategories.

val windowSpec = Window.partitionBy("name").orderBy("count")
sqlContext
    .createDataFrame(
      Seq[(String, Int)](
        ("A", 1),
        ("A", 2),
        ("A", 3),
        ("B", 10),
        ("B", 20),
        ("B", 30)
      ))
    .toDF("name", "count")
    .withColumn("firstCountOfName", first("count").over(windowSpec))
    .withColumn("lastCountOfName", last("count").over(windowSpec))
    .show()

returns me something strange:

+----+-----+----------------+---------------+                                   
|name|count|firstCountOfName|lastCountOfName|
+----+-----+----------------+---------------+
|   B|   10|              10|             10|
|   B|   20|              10|             20|
|   B|   30|              10|             30|
|   A|    1|               1|              1|
|   A|    2|               1|              2|
|   A|    3|               1|              3|
+----+-----+----------------+---------------+

As we can see, the first value returned is correctly computed, but the last isn't, it's always the current value of the column.

Has someone a solution to do what I want?

Upvotes: 5

Views: 6815

Answers (1)

Daniel de Paula
Daniel de Paula

Reputation: 17872

According to the issue SPARK-20969, you should be able to get the expected results by defining adequate bounds to your window, as shown below.

import org.apache.spark.sql.expressions.Window
import org.apache.spark.sql.functions._

val windowSpec = Window
  .partitionBy("name")
  .orderBy("count")
  .rowsBetween(Window.unboundedPreceding, Window.unboundedFollowing)

sqlContext
  .createDataFrame(
    Seq[(String, Int)](
      ("A", 1),
      ("A", 2),
      ("A", 3),
      ("B", 10),
      ("B", 20),
      ("B", 30)
    ))
  .toDF("name", "count")
  .withColumn("firstCountOfName", first("count").over(windowSpec))
  .withColumn("lastCountOfName", last("count").over(windowSpec))
  .show()

Alternatively, if your are ordering on the same column you are computing first and last, you can change for min and max with a non-ordered window, then it should also work properly.

Upvotes: 9

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