Reputation: 906
What is the difference between initializing a string with:
std::string testString = "Test";
and
std::string testString{"Test"};
Is this only syntactic sugar thing or there actually are some performance related differences?
Upvotes: 2
Views: 560
Reputation: 371
I found a clear answer in Herb Sutter
https://herbsutter.com/2013/05/09/gotw-1-solution/
Upvotes: 0
Reputation: 1401
There is no difference in this particular case. But try
std::string s1(1, '0'); // calls string(size_type , char )
std::string s2{1, '0'}; // calls string(std::initializer_list<char> )
assert(s1.length() == 1 && s1[0] == '0');
assert(s2.length() == 2 && s2[0] == '\x1');
or with std::vector
std::vector<int> v1(1); // calls vector(size_type )
std::vector<int> v2{1}; // calls vector(std::initializer_list<int> )
assert(v1.size() == 1 && v1[0] == 0);
assert(v2.size() == 1 && v2[0] == 1);
Upvotes: 2
Reputation: 614
There is no difference between them.
First declaration is preferred in most projects due to the syntax highlighting.
Upvotes: 0
Reputation: 21510
The {}
initialization syntax is known as the uniform initialization syntax, it has a few key differences, but in your code as is they both do the same thing - construct a std::string
object from the string literal "Test"
Initializing an object with an assignment is essentially the same as putting the right hand side in parentheses and constructing the object. For example the below two are the same
T obj = a;
T obj(a);
So you should be asking yourself, what is the difference between constructing a string object the following two ways
std::string{"Test"};
std::string("Test");
And the answer is that both the constructions above are the same and call the same constructor for std::string
For more on uniform initialization see https://softwareengineering.stackexchange.com/questions/133688/is-c11-uniform-initialization-a-replacement-for-the-old-style-syntax
Upvotes: 4