Reputation: 4823
I'm trying to unzip a zip file directly from the php://input
stream. I'm running Laravel Homestead, PHP 7.1.3-3+deb.sury.org~xenial+1
, with an endpoint at myproject.app/upload
, here is the curl
command:
curl --request POST \
--url 'http://myproject.app/upload' \
--data-binary "@myfile.zip" \
Here is a list of all the methods I've tried, which all fail:
dd(file_get_contents('compress.zlib://php://input'));
file_get_contents(): cannot represent a stream of type Input as a File Descriptor
$fh = fopen('php://input', 'rb');
stream_filter_append($fh, 'zlib.inflate', STREAM_FILTER_READ, array('window'=>15));
$data = '';
while (!feof($fh)) {
$data .= fread($fh, 8192);
}
dd($data);
""
$zip = new ZipArchive;
$zip->open('php://input');
$zip->extractTo(storage_path() . '/' . 'myfile');
$zip->close();
ZipArchive::extractTo(): Invalid or uninitialized Zip object
Here are all the links I've found on the subject:
http://php.net/manual/en/wrappers.php#83220
http://php.net/manual/en/wrappers.php#109657
http://php.net/manual/en/wrappers.compression.php#118461
https://secure.phabricator.com/rP42566379dc3c4fd01a73067215da4a7ca18f9c17
https://arjunphp.com/how-to-unpack-a-zip-file-using-php/
I'm beginning to think that it's not possible to operate on streams with PHP's built-in zip functionality. The overhead and complexity of writing temporary files would be pretty disappointing. Does anyone know how to do this, or is it a bug?
Upvotes: 6
Views: 4397
Reputation: 4823
After more research, I discovered the answer, but it's not satisfactory. Due to one of the great blunders of the modern world, gzip and zip are not the same format. gzip encodes a single file (that's why we often see tar.gz), while zip encodes files and folders. I was trying to upload a zip file and decode it with gzip, which doesn't work. More info:
https://stackoverflow.com/a/20765054/539149
https://stackoverflow.com/a/1579506/539149
The other part of this issue is that PHP neglected to provide a stream filter for gzip:
https://stackoverflow.com/a/11926679/539149
So even though gzopen('php://temp', 'rb')
works, gzopen('php://input', 'rb')
does not because the input stream is not rewindable. This makes it impossible to operate on an in-memory stream, because there is no way to write data to a stream and then read unzipped data on a separate gzip connection to that stream. Which means the following code does not work:
$input = fopen("php://input", "rb");
$temp = fopen("php://temp", "rb+");
stream_copy_to_stream($input, $temp);
rewind($temp);
dd(stream_get_contents(gzopen('php://temp', 'rb')));
People have attempted various workarounds, but they all do bit fiddling:
http://php.net/manual/en/function.gzopen.php#105676
http://php.net/manual/en/function.gzdecode.php#112200
I did manage to get a pure in-memory solution to work, but since it's not possible to use streams, a needless copy occurs:
// works (stream + string)
dd(gzdecode(file_get_contents('php://input')));
// works (stream + file)
dd(stream_get_contents(gzopen(storage_path() . '/' . 'myfile.gz', 'rb')));
// works (stream + file)
dd(file_get_contents('compress.zlib://' . storage_path() . '/' . 'myfile.gz'));
// doesn't work (stream)
dd(stream_get_contents(gzopen('php://input', 'rb')));
// doesn't work (stream + filter)
dd(file_get_contents('compress.zlib://php://input'));
Without a working example, I have to assume that PHP's zip implementation is incomplete because it can't operate on streams. If anyone has more information, I'm happy to revisit this.
Upvotes: 8