Reputation: 161
if I have a dictionary
x ={0: 0, 1: 4, 2: 0, 3: 2, 4: 2, 5: 4}
how do i get the keys of all the largest values
In this case they would be 1 and 5 .
Not a duplicate question. looking to find all the keys and not just the one.
Upvotes: 2
Views: 726
Reputation: 1653
x ={0: 0, 1: 4, 2: 0, 3: 2, 4: 2, 5: 4}
maximum = max(x.values())
keys = [key for key, value in x.items() if value == maximum]
print(keys) # => [1, 5]
Upvotes: 3
Reputation: 114290
There is a class in collections
called Counter
that does exactly what you want. It provides the exact functionality you require via it's most_common
method:
from collections import counter
maxes = Counter(x).most_common(2)
print([x[0] for x in maxes])
[1, 5]
Now this is probably not exactly what you want because I hard coded in the number 2. You can get this by using another Counter
on the values of your dictionary!
x = Counter(x) # This preserves x: just makes it a subclass of dict
max_count = Counter(x.values())[x.most_common(1)[0][1]]
maxes = x.most_common(max_count)
maxes = [x[0] for x in maxes]
Here, I compute the number of times that the most common value occurs by counting all the different values, and then checking the maximum one using x.most_common(1)[0][1]
.
Please do not select this answer. @BrightOne has the right answer. This is just a thing I did to see if I could avoid using anything but Counters. It is not actually a good idea.
Upvotes: 1