Reputation: 973
func main(){
var array [10]int
sliceA := array[0:5]
append(sliceA, 4)
fmt.Println(sliceA)
}
Error : append(sliceA, 4) evaluated but not used
I don't Know why? The slice append operation is not run...
Upvotes: 97
Views: 67547
Reputation: 2627
Refer: Appending to and copying slices
In Go, arguments are passed by value.
Typical append
usage is:
a = append(a, x)
You need to write:
func main(){
var array [10]int
sliceA := array[0:5]
// append(sliceA, 4) // discard
sliceA = append(sliceA, 4) // keeping return value is mandatory
fmt.Println(sliceA)
}
Output:
[0 0 0 0 0 4]
Upvotes: 142
Reputation: 161
sliceA = append(sliceA, 4)
append()
returns a slice containing one or more new values.
Note that we need to accept a return value from append as we may get a new slice value.
Upvotes: 16
Reputation: 143
The key to understand is that slice is just a "view" of the underling array. You pass that view to the append function by value, the underling array gets modified, at the end the return value of append function gives you the different view of the underling array. i.e. the slice has more items in it
your code
sliceA := array[0:5] // sliceA is pointing to [0,5)
append(sliceA, 4) // sliceA is still the original view [0,5) until you do the following
sliceA = append(sliceA, 4)
reference: https://blog.golang.org/slices
Upvotes: 1
Reputation: 81
you may try this:
sliceA = append(sliceA, 4)
built-in function append([]type, ...type)
returns an array/slice of type, which should be assigned to the value you wanted, while the input array/slice is just a source. Simply, outputSlice = append(sourceSlice, appendedValue)
Upvotes: 4
Reputation: 7535
Per the Go docs:
The resulting value of append is a slice containing all the elements of the original slice plus the provided values.
So the return value of 'append', will contain your original slice with the appended portion.
Upvotes: 2