Reputation: 2264
Given the input like:
<root>
<childA style="style_1">Some</childA>
<childA style="style_1">Text</childA>
<childA style="style_1">Here</childA>
<childB style="style_2"/>
<childA style="style_2">Fake</childA>
<childB style="style_2"/>
<childA style="style_1">Some</childA>
<childA style="style_1">Other</childA>
<childB style="style_2"/>
<childA style="style_1">Text</childA>
<parent>
<childA style="style_1">More</childA>
<childA style="style_1">Text</childA>
</parent>
</root>
How do I merge elements that are following each other? So the desired output is:
<root>
<childA style="style_1">SomeTextHere</childA>
<childB style="style_2"/>
<childA style="style_2">Fake</childA>
<childB style="style_2"/>
<childA style="style_1">SomeOther</childA>
<childB style="style_2"/>
<childA style="style_1">Text</childA>
<parent>
<childA style="style_1">MoreText</childA>
</parent>
</root>
I tried different tricks with for-each-group
and for-each
inside of it, but got duplicated nodes and also that <childB>
between two <childA>
nodes was ignored when I used group-adjacent="@style"
and I got SomeOtherText
in one node instead of two nodes.
Here's my attempt:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output indent="yes" />
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="childA">
<xsl:copy-of select="." />
</xsl:template>
<xsl:template match="childB">
<xsl:copy-of select="." />
</xsl:template>
<xsl:template match="parent">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[childA]">
<xsl:copy>
<xsl:for-each-group select="childA" group-adjacent="@style">
<xsl:element name="childA">
<xsl:attribute name="style">
<xsl:value-of select="current-grouping-key()"/>
</xsl:attribute>
<xsl:for-each select="current-group()">
<xsl:value-of select="."/>
</xsl:for-each>
</xsl:element>
</xsl:for-each-group>
</xsl:copy>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
Upvotes: 0
Views: 729
Reputation: 180103
You can do this (as clarified in comments) without relying on XSLT 2.0 or 3.0 features, though perhaps at a performance penalty vs. the best available with a later version. You simply need to know how to write an XPath expression that distinguishes the first <childA>
in each group from the rest, or vise versa. For example:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="childA">
<!-- this is the first childA in a group -->
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select="." mode = "merge"/>
</xsl:copy>
</xsl:template>
<!-- Matches (only) the second and subsequent members of a childA group: -->
<xsl:template match="childA[name(preceding-sibling::*[1]) = 'childA' and @style = preceding-sibling::*[1]/@style]"/>
<!-- merge in this childA's content and that of the remaining group elements -->
<xsl:template match="childA" mode="merge">
<xsl:apply-templates select="node()"/> <!-- attributes ignored -->
<!-- merge the next sibling, too, if it's in the same group: -->
<xsl:apply-templates select="following-sibling::*[1][name() = 'childA' and @style = preceding-sibling::*[1]/@style]" mode = "merge"/>
</xsl:template>
</xsl:stylesheet>
Upvotes: 1
Reputation: 116957
How about:
XSLT 2.0
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<!-- identity transform -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[childA]">
<xsl:copy>
<xsl:for-each-group select="*" group-adjacent="concat(name(), '|', @style)">
<xsl:choose>
<xsl:when test="self::childA">
<childA style="{@style}">
<xsl:value-of select="current-group()" separator=""/>
</childA>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Upvotes: 3
Reputation: 167471
Using XSLT 3.0 (like supported by Saxon 9.8 or actual Altova) I think you want:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:math="http://www.w3.org/2005/xpath-functions/math" exclude-result-prefixes="xs math"
version="3.0">
<xsl:output indent="yes"/>
<xsl:mode on-no-match="shallow-copy"/>
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:for-each-group select="*"
group-adjacent="node-name() eq xs:QName('childA'), @style" composite="yes">
<xsl:choose>
<xsl:when test="current-grouping-key()[1]">
<xsl:copy>
<xsl:apply-templates select="@*, current-group()/node()"/>
</xsl:copy>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Upvotes: 0