CODEWITHSUNDEEP
javaregex
giograno
giograno

Reputation: 1809

Java Regex match between string and a space

I have the following string in Java.

ActivityRecord{7615a77 u0 com.example.grano.example_project/.MainActivity t20}

My need is to get the string MainActivity, ie the part between the ./ and the space after the word.

So basically I'm looking for a regular expression able to catch something in the middle of given characters and a white space.

Upvotes: 0

Views: 1341

Answers (3)

Michael
Michael

Reputation: 44150

You can use the expression:

(?<=\/\.)\w+?(?=\s)

Broken down:

(?<=  \/\.  )
 ^ lookbehind
       ^ for a literal / followed by a literal .

\w  +?
 ^ word character
    ^ one or more (non-greedy)

(?=  \s  )
 ^ lookahead
     ^ a whitespace character

Test it here.

Upvotes: 1

Youcef LAIDANI
Youcef LAIDANI

Reputation: 59978

You can use a regex like this /\.(.*?)\s with pattern like :

String str = ...;
String regex = "/\\.(.*?)\\s";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(str);

while (matcher.find()) {                                                
    System.out.println(matcher.group(1));
    //-------------------------------^-----get the group (.*?) between '/.' and 'space'
}

Output

MainActivity

Upvotes: 1

Austin_Anderson
Austin_Anderson

Reputation: 940

Assuming your proceeding text doesn't have / in it and the text you want to isolate doesn't have a space in it, you can use this

replaceAll("^[^/]*/\\.([^ ]*).*$","$1"));

which looks from the start for the first /, then /., then captures everything up to the first space from that point, and then matches everything else, and replaces it all with the capture

Upvotes: 1

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