Reputation: 4377
I have pixmap:
pixmap = self._screen.grabWindow(0,
self._x, self._y,
self._width, self._height)
I want to convert it to OpenCV format.
I tried to convert it to numpy.ndarray
as described here but I got error sip.voidptr object has an unknown size
Is there any way to get numpy array (same format as cv2.VideoCapture
read
method returns)?
Upvotes: 9
Views: 9793
Reputation: 359
Heres a function:
def QPixmapToArray(pixmap):
## Get the size of the current pixmap
size = pixmap.size()
h = size.width()
w = size.height()
## Get the QImage Item and convert it to a byte string
qimg = pixmap.toImage()
byte_str = qimg.bits().tobytes()
## Using the np.frombuffer function to convert the byte string into an np array
img = np.frombuffer(byte_str, dtype=np.uint8).reshape((w,h,4))
return img
Upvotes: 1
Reputation: 4530
The copy can be avoided by doing:
channels_count = 4
pixmap = self._screen.grabWindow(0, self._x, self._y, self._width, self._height)
image = pixmap.toImage()
b = image.bits()
# sip.voidptr must know size to support python buffer interface
b.setsize(self._height * self._width * channels_count)
arr = np.frombuffer(b, np.uint8).reshape((self._height, self._width, channels_count))
Upvotes: 6
Reputation: 4377
I got numpy array using this code:
channels_count = 4
pixmap = self._screen.grabWindow(0, self._x, self._y, self._width, self._height)
image = pixmap.toImage()
s = image.bits().asstring(self._width * self._height * channels_count)
arr = np.fromstring(s, dtype=np.uint8).reshape((self._height, self._width, channels_count))
Upvotes: 8