CODEWITHSUNDEEP
racket
user8286060
user8286060

Reputation: 57

How to fix the function single integer as an argument in Racket

I need some one can explain for me to how to do this please,

divisible-by-7?

Define your own Racket function that takes a single integer as an argument and returns a Boolean that indicates whether the number is evenly divisible by 7. You do not have to perform error checking on the input.

Input: An integer.

Output: A Boolean.

Example:

> (divisible-by-7? 14)
#t
> (divisible-by-7? 31)
#f
> (divisible-by-7? 56)
#t

this what I have but I keep receiving error 

(define (divisible-by-7)
(divisible 7))

Upvotes: 1

Views: 740

Answers (1)

fantasie
fantasie

Reputation: 257

It seems that divisible is not a library procedure in racket.

Try

(define (divide-by-7? x)
  (= (remainder x 7) 0))

Alternatively, if you would like to implement divisible? in racket:

(define (divisible k)
  (lambda (x)
    (= (remainder x k) 0)))

and to use it:

(define divide-by-7?
  (divisible 7))

Upvotes: 0

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