CODEWITHSUNDEEP
flutterflutter-dependencies
karan vs
karan vs

Reputation: 3364

How to get unique device id in flutter?

In Android we have, Settings.Secure.ANDROID_ID. I do not know the iOS equivalent. Is there a flutter plugin or a way to get a unique device id for both Android and IOS in flutter?

Upvotes: 137

Views: 216272

Answers (14)

CopsOnRoad
CopsOnRoad

Reputation: 267384

Null safe code

Use device_info_plus plugin developed by Flutter community. This is how you can get IDs on both platform.

In your pubspec.yaml file add this:

dependencies:
  device_info_plus: ^10.1.2
  android_id: ^0.4.0

Create a method:

import 'package:android_id/android_id.dart';
import 'package:device_info_plus/device_info_plus.dart';

Future<String?> _getId() async {
  var deviceInfo = DeviceInfoPlugin();
  if (Platform.isIOS) { // import 'dart:io'
    var iosDeviceInfo = await deviceInfo.iosInfo;
    return iosDeviceInfo.identifierForVendor; // unique ID on iOS
  } else if(Platform.isAndroid) {
    var androidDeviceInfo = await deviceInfo.androidInfo;
    return AndroidId().getId(); // unique ID on Android
  }
}

Usage:

String? deviceId = await _getId();

Upvotes: 148

cansu
cansu

Reputation: 1144

As of 2024, June, I started to use app_set_id package. It is compatible with latest dart and flutter versions.

As of 2022, December, last status about getting device id :

device_info_plus don't give unique device id anymore. So I started to use platform_device_id package.

I tested it on Android and it worked as same as device_info previously and provide the same id value. It also has a simple usage :

   String deviceId = await PlatformDeviceId.getDeviceId;

This package uses updated android embedding version and also has null safety support.

Upvotes: 18

blake
blake

Reputation: 601

It's 2023, UUIDs are still hard apparently.

Use https://pub.dev/packages/app_set_id which uses the Android AppSetID and the iOS IDfV.

Each of android_id, device_info, device_info_plus have major issues, as described in other answers here.

Upvotes: 3

Asim Khan
Asim Khan

Reputation: 365

In You Main.dart File Just these codes You will Get the Player Id of the Your Flutter App//

  final status = await OneSignal.shared.getDeviceState();` final String? osUserID = status?.userId;

print(osUserID);

Upvotes: 0

Pratik Butani
Pratik Butani

Reputation: 62391

Latest:

The plugin device_info has given deprecation notice and replaced by device_info_plus

Example:

dependencies:
  device_info_plus: ^9.0.2

How to use:

import 'package:device_info_plus/device_info_plus.dart';

DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();

AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
print('Running on ${androidInfo.model}');  // e.g. "Moto G (4)"

IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
print('Running on ${iosInfo.utsname.machine}');  // e.g. "iPod7,1"

WebBrowserInfo webBrowserInfo = await deviceInfo.webBrowserInfo;
print('Running on ${webBrowserInfo.userAgent}');  // e.g. "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:61.0) Gecko/20100101 Firefox/61.0"

You can check here full example:

For Unique ID:

You can use following code to get Unique ID:

String deviceIdentifier = '';
DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();
if (kIsWeb) {
  final WebBrowserInfo webInfo = await deviceInfo.webBrowserInfo;
  deviceIdentifier = webInfo.vendor! +
      webInfo.userAgent! +
      webInfo.hardwareConcurrency.toString();
} else {
  if (Platform.isAndroid) {
    final AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
    deviceIdentifier = androidInfo.id;
  } else if (Platform.isIOS) {
    final IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
    deviceIdentifier = iosInfo.identifierForVendor!;
  } else if (Platform.isLinux) {
    final LinuxDeviceInfo linuxInfo = await deviceInfo.linuxInfo;
    deviceIdentifier = linuxInfo.machineId!;
  }
}

edit: There is no androidId on since v4.1.0.

Upvotes: 10

Sanny khan
Sanny khan

Reputation: 383

android_id: ^0.1.3+1 Use this package but it only works on android.

device_info_plus: ^8.0.0 Use this package it works on IOS, Android, Web.

Upvotes: 3

Chaythanya Nair
Chaythanya Nair

Reputation: 5064

There is a plugin called device_info. You can get it here.

Check the official example here

 static Future<List<String>> getDeviceDetails() async {
    String deviceName;
    String deviceVersion;
    String identifier;
    final DeviceInfoPlugin deviceInfoPlugin = new DeviceInfoPlugin();
    try {
      if (Platform.isAndroid) {
        var build = await deviceInfoPlugin.androidInfo;
        deviceName = build.model;
        deviceVersion = build.version.toString();
        identifier = build.androidId;  //UUID for Android
      } else if (Platform.isIOS) {
        var data = await deviceInfoPlugin.iosInfo;
        deviceName = data.name;
        deviceVersion = data.systemVersion;
        identifier = data.identifierForVendor;  //UUID for iOS
      }
    } on PlatformException {
      print('Failed to get platform version');
    }

//if (!mounted) return;
return [deviceName, deviceVersion, identifier];
}

You can store this UUID in the Keychain. This way you can set an unique ID for your device.

UPDATE

device_info is now device_info_plus

Upvotes: 101

李华良
李华良

Reputation: 264

androidID is removed since v4.1.0. Check the changelog.

android_id package is recommanded to get the correct androidId.

Upvotes: 7

Ariel
Ariel

Reputation: 2742

Use device_info_plus package developed by Flutter community. This is how you can get IDs on both platform.

In your pubspec.yaml file add this:

dependencies:
  device_info_plus: ^3.2.3

Create a method:

Future<String> getUniqueDeviceId() async {
  String uniqueDeviceId = '';

  var deviceInfo = DeviceInfoPlugin();

  if (Platform.isIOS) { // import 'dart:io'
    var iosDeviceInfo = await deviceInfo.iosInfo;
    uniqueDeviceId = '${iosDeviceInfo.name}:${iosDeviceInfo.identifierForVendor}'; // unique ID on iOS
  } else if(Platform.isAndroid) {
    var androidDeviceInfo = await deviceInfo.androidInfo;
    uniqueDeviceId = '${androidDeviceInfo.name}:${androidDeviceInfo.id}' ; // unique ID on Android
  }
  
  return uniqueDeviceId;

}

Usage:

String deviceId = await getUniqueDeviceId();

Output:

M2102J20SG::SKQ1.211006.001

Note:

  1. Do not use androidDeviceInfo.androidId. This would change when your mac address changes. Mobile devices above Android OS 10/11 will generate a randomized MAC. This feature is enabled by default unless disabled manually. This would cause the androidId to change when switiching networks. You can confirm this by yourself by changing androidDeviceInfo.id to androidDeviceInfo.androidId above.

  2. you can probably get away with using only androidDeviceInfo.name as it would not change ever.

  3. androidDeviceInfo.id can also change if OS is updated as it is an android os version.

  4. androidDeviceInfo.androidId should only be used if device uses fix mac address as mentioned in point 1. Otherwise, either use *.name only or androidDeviceInfo.id alongside with *.name.

Upvotes: 7

Gowtham. R
Gowtham. R

Reputation: 788

Add the following code in your .yaml file.

device_info_plus: ^1.0.0

I used the following approach to get the device info that support in all platforms (i.e.) Android, IOS and Web.

import 'dart:io';  
import 'package:device_info_plus/device_info_plus.dart';  
import 'package:flutter/foundation.dart' show kIsWeb;  

Future<String> getDeviceIdentifier() async { 

    String deviceIdentifier = "unknown";  
    DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();  

    if (kIsWeb) {
      WebBrowserInfo webInfo = await deviceInfo.webBrowserInfo;
      deviceIdentifier = webInfo.vendor +
          webInfo.userAgent +
          webInfo.hardwareConcurrency.toString();
    } else {
      if (Platform.isAndroid) {
        AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
        deviceIdentifier = androidInfo.androidId;
      } else if (Platform.isIOS) {
        IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
        deviceIdentifier = iosInfo.identifierForVendor;
      } else if (Platform.isLinux) {
        LinuxDeviceInfo linuxInfo = await deviceInfo.linuxInfo;
        deviceIdentifier = linuxInfo.machineId;
      }
    }
    return deviceIdentifier;
}

Upvotes: 5

KentChien
KentChien

Reputation: 61

I release a new flutter plugin client_information might help. It provide a simple way to get some basic device information from your application user.

  1. add to pubspec.yaml
  dependencies:
    ...
    client_information: ^1.0.1
  1. import to your project
import 'package:client_information/client_information.dart';
  1. then you can get device ID like this
/// Support on iOS, Android and web project
Future<String> getDeviceId() async {
  return (await ClientInformation.fetch()).deviceId;
}

Upvotes: 6

Oswin Noetzelmann
Oswin Noetzelmann

Reputation: 9545

Update 1/3/2021: The recommended way is now the extended community plugin called device_info_plus. It supports more platforms than device_info and aims to support all that are supported by flutter. Here is an example usage:

import 'package:flutter/foundation.dart' show kIsWeb;
import 'package:device_info_plus/device_info_plus.dart';
import 'dart:io';

Future<String> getDeviceIdentifier() async {
  String deviceIdentifier = "unknown";
  DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();

  if (Platform.isAndroid) {
    AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
    deviceIdentifier = androidInfo.androidId;
  } else if (Platform.isIOS) {
    IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
    deviceIdentifier = iosInfo.identifierForVendor;
  } else if (kIsWeb) {
    // The web doesnt have a device UID, so use a combination fingerprint as an example
    WebBrowserInfo webInfo = await deviceInfo.webBrowserInfo;
    deviceIdentifier = webInfo.vendor + webInfo.userAgent + webInfo.hardwareConcurrency.toString();
  } else if (Platform.isLinux) {
    LinuxDeviceInfo linuxInfo = await deviceInfo.linuxInfo;
    deviceIdentifier = linuxInfo.machineId;
  } 
  return deviceIdentifier;
}

Upvotes: 20

user9740540
user9740540

Reputation:

Use device_id plugin

  1. Add in your following code in your .yaml file.

    device_id: ^0.1.3

  2. Add import in your class

    import 'package:device_id/device_id.dart';

  3. Now get device id from:

    String deviceid = await DeviceId.getID;

Upvotes: 7

Collin Jackson
Collin Jackson

Reputation: 116708

If you're serving ads you can use ASIdentifierManager. You should only use it for ads. There is no general UDID mechanism provided by the OS on iOS, for privacy reasons.

If you're using firebase_auth plugin you could signInAnonymously and then use the id of the FirebaseUser. This will give you an identifier that is specific to your Firebase app.

Upvotes: -2

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