CODEWITHSUNDEEP
pythonpython-2.7
Nicholas
Nicholas

Reputation: 1143

TypeError when trying to call function inside function with **kwargs?

I'm confused about why this error is occurring:

TypeError: func1() takes exactly 0 arguments (1 given)

The code is as follows:

def func1(**kwargs):
    if kwargs['dog'] != 2:
        return False
    return True

def func2(**kwargs):
    if kwargs['cat'] != 3:
        return False
    return True

def func3(*listOfFuncs, **extraArgs):
    for func in listOfFuncs:
        if func(extraArgs) == False:
            print 'break'
            break
        print 'continue'
        continue

func3(func1, func2, dog=2, cat=1)

I'm trying to pass function names as arguments to func3. I also want to pass both 'cat' and 'dog' keyword arguments to both func1 and func2 when they are called in fun3 but only use a single keyword argument in each of those functions?

Any help would be appreciated

Upvotes: 1

Views: 116

Answers (1)

Jignesh Jarsaniya
Jignesh Jarsaniya

Reputation: 589

You have to pass the **kwargs args at the time of function call.

I have just reviewed your code. Please try following

def func1(**kwargs):
    if kwargs['dog'] != 2:
        return False
    return True

def func2(**kwargs):
    if kwargs['cat'] != 3:
        return False
    return True

def func3(*listOfFuncs, **extraArgs):
    print 
    for func in listOfFuncs:
        if func(**extraArgs) == False:
            print 'break'
            break
        print 'continue'
        continue

func3(func1, func2, dog=2, cat=1)

Output :

continue
break

Upvotes: 2

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