CODEWITHSUNDEEP
javaperformancelistjava-8
proceder
proceder

Reputation: 57

The best way to sort list by item name length

Which of this ways is the best, looking at speed and comfort? 

names.sort( (a,b) -> a.getName().length() - b.getName().length() );


Collections.sort(names, Comparator.comparing( s -> Celebrity.getName().length() ))


BiFunction<Celebrity,Celebrity,Integer> bifunc = (a,b) -> Integer.compare(a.getName().length(), b.getName().length());
Collections.sort( names, bifunc::apply );

Upvotes: 2

Views: 177

Answers (1)

Gondy
Gondy

Reputation: 5295

It's the same. look at Collections.sort method :

public static <T> void sort(List<T> list, Comparator<? super T> c) {
   list.sort(c);
}

All 3 approaches are sorted by the same algorithm.

You should write code as much as readable as possible. Don't do premature micro-optimalizations unless really needed.

I would use this one line:

names.sort(Comparator.comparingInt(celebrity -> celebrity.getName().length()));

Upvotes: 10

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