CODEWITHSUNDEEP
pythonpython-2.7python-imaging-library
Derek Halden
Derek Halden

Reputation: 2323

Get Image Filename from Image PIL

Is it possible to get the filename of an Image I have already opened from an Image object? I checked the API, and the best I could come up with was the PIL.Image.info, but that appears to be empty when I check it. Is there something else I can use to get this info in the PIL Image library?

(Yes, I realize I can pass the filename into the function. I am looking for another way to do this.)

i.e.

from PIL import Image

def foo_img(img_input):
  filename = img_input.info["filename"]
  # I want this to print '/path/to/some/img.img'
  print(filename) 

foo_img(Image.open('/path/to/some/img.img'))

Upvotes: 21

Views: 52435

Answers (3)

Nicolae
Nicolae

Reputation: 432

Another way how I did it is by using the initial file location:

def getImageName(file_location):
    filename = file_location.split('/')[-1]
    location = file_location.split('/')[0:-1]
    filename = filename.split('.')
    filename[0] += "_resized"
    filename = '.'.join(filename)
    new_path = '/'.join(location) + '/' + filename
    return new_path

Upvotes: 2

dasdachs
dasdachs

Reputation: 719

The Image object has a filename attribute.

 from PIL import Image


 def foo_img(img_input):
     print(img_input.filename)

 foo_img(Image.open('/path/to/some/img.img'))

Upvotes: 8

Mark Ransom
Mark Ransom

Reputation: 308158

I don't know if this is documented anywhere, but simply using dir on an image I opened showed an attribute called filename:

>>> im = Image.open(r'c:\temp\temp.jpg')
>>> im.filename
'c:\\temp\\temp.jpg'

Unfortunately you can't guarantee that attribute will be on the object:

>>> im2 = Image.new('RGB', (100,100))
>>> im2.filename
Traceback (most recent call last):
  File "<pyshell#50>", line 1, in <module>
    im2.filename
AttributeError: 'Image' object has no attribute 'filename'

You can get around this problem using a try/except to catch the AttributeError, or you can test to see if the object has a filename before you try to use it:

>>> hasattr(im, 'filename')
True
>>> hasattr(im2, 'filename')
False
>>> if hasattr(im, 'filename'):
    print(im.filename)

c:\temp\temp.jpg

Upvotes: 32

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