CODEWITHSUNDEEP
djangodjango-templatesdjango-urls
Anupam
Anupam

Reputation: 15620

Access kwargs from a URL in a Django template

Can I access value of a named argument (from the URL) in a Django template?

Like can I access the value of this_name below from a django template?

url(r'^area/(?P<this_name>[\w-]+)/$', views.AreaView.as_view(), name="area_list")

I could get the whole URL path and break it up but wanted to check if there's a straight forward way to do that, since it already has a name.

Passing it down in the context data from the view may be an alternative but not sure if I do need to pass it down since I'd guess the template would already have it somehow? Couldn't find a direct method in the request API though.

Upvotes: 29

Views: 25337

Answers (2)

suhailvs
suhailvs

Reputation: 21740

another way to access it is:

{{request.resolver_match.kwargs.this_name}}

Upvotes: 0

Alasdair
Alasdair

Reputation: 309089

In the view, you can access the URL args and kwargs as self.args and self.kwargs.

class MyView(View):
    def my_method(self):
        this_name = self.kwargs['this_name']

If you only want to access the value in the template, then you don't need to make any changes in the view. The base get_context_data method adds the view to the context as view, so you can add the following to your template:

{{ view.kwargs.this_name }}

Upvotes: 56

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